node.js Express - 如何异步获取部分视图 [英] node.js Express - How to get partial views asynchronously

问题描述

我有一个布局 - 导航菜单。在快速教程中，只有旧版页面加载。整个旧页面被丢弃，并且下载了一个新的页面，其中包含所有布局，视图和部分视图。我想要导航菜单留下来。那我该怎么办呢？

如果我可能弄错这个网页架构，请指导我。

解决方案

@drachenstern表示，您只想渲染部分HTML片段，而不是整个文档，包括布局。您可以通过以下方式告诉express：跳过布局：

  res.render（'sometemplate'，{layout：false}）; 
  

如果要查找与全页浏览器加载不同的Ajax请求，请使用 req.xhr 标志如下所示

因此，您甚至可以执行

  res.render （'sometemplate'，{layout：！req.xhr}）; 
  

I've got a layout - navigation menu. In express tutorials theres only old-school pages loading. whole old page is thrown away and a new one is downloaded with all layouts,views and partial views. And i want navigation menu to stay. So how can i do that?

If i'm maybe getting smth wrong with this web pages architecture please guide me.

解决方案

As @drachenstern said, you want to render only partial HTML fragments, not whole documents including the layout. You can tell express to skip the layout using:

res.render('sometemplate', {layout: false});

If you want to look for Ajax requests as distinct from full-page browser loads, use the req.xhr flag as documented here

Thus you might even be able to do

res.render('sometemplate', {layout: !req.xhr});

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