python regex只匹配最后一次 [英] python regex match only last occurrence
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问题描述
>>> re.findall('(\(\w +,\d + \)(?:,)?)+','(a,b),(c,d),(e,f)')
['(e,f)']
我想要得到其他项目好吧
帮助将真正的appriciated
解决方案
删除 +
;您的模式匹配所有事件,但该组只能捕获一次,您不能以这种方式重复捕获组:
>>> import re
>>> re.findall('(\(\w +,\w + \),?)+','(a,b),(c,d),(e,f)')
[ '(e,f)']
>>> re.findall('\(\w +,\w + \),?','(a,b),(c,d),(e,f)')
['(a ,b),','(c,d),','(e,f)']
在那里我用 \w
替换 \d
来演示,并删除冗余非捕获组周围逗号。最外面的捕获组也是多余的;没有它, re.findall()
返回整个匹配的表达式。
I'm experiencing some problems implementing a regular expression for a repeating string pattern.
>>> re.findall('(\(\w+,\d+\)(?:,)?)+', '(a,b),(c,d),(e,f)')
['(e,f)']
I would like ro get the other items as well
Help would be really appriciated
解决方案
Remove the +
; your pattern matches all occurrences, but the group can only capture one occurrence, you cannot repeat a capturing group that way:
>>> import re
>>> re.findall('(\(\w+,\w+\),?)+', '(a,b),(c,d),(e,f)')
['(e,f)']
>>> re.findall('\(\w+,\w+\),?', '(a,b),(c,d),(e,f)')
['(a,b),', '(c,d),', '(e,f)']
where I replaced the \d
with \w
to demonstrate, and removed the redundant non-capturing group around the comma. The outermost capturing group is also redundant; without it, re.findall()
returns the whole matched expression.
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