如何分解表达式以满足通用属性更改方法? [英] How to decompose expression to satisfy generic property change method?

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问题描述

我有一个实现 INotifyPropertyChanged 的基础EF实体类。

I have a base EF entity class which implements INotifyPropertyChanged.

基本属性Id是我的示例:

The base property, Id is my example:

  /// <summary>
  /// Entity Id
  /// </summary>
  public int Id {
     get { return id; }
     set { SetValue<int>(() => (Id != value), (v) => id = v); } // < can this be simplified into a single call?
  }

...定义了SetValue:

...where SetValue is defined:

  protected void SetValue<TValue>(Expression<Func<bool>> evalExpr, Action<TValue> set) {
     // Compile() returns a Func<bool>
     var doSetValue = evalExpr.Compile();

     if (doSetValue()) {
        var expr = evalExpr.Body as BinaryExpression;
        //  this is not compiling - how do I decompose the expression to get what I need?
        var propertyName = ((PropertyExpression)expr.Left).Name;
        var assignValue = (TValue)((ConstantExpression)expr.Right).Value;

        set(assignValue);
        _propertyChangedHandler(this, new PropertyChangedEventArgs(propertyName));
     }
  }

我可以找到的所有样本都是期望的参数。我更喜欢setter(SetValue调用)尽可能的简单 - 即有没有办法将输入参数减少到1?

All samples I can find are expecting parameters. I prefer that the setter (SetValue call) is as simple as possible - i.e., is there a way to reduce the input parameter to 1?

推荐答案

您应该更改

var propertyName = ((PropertyExpression)expr.Left).Name;

var propertyName = ((MemberExpression)expr.Left).Member.Name;

您的代码编译,但您所做的是不是最佳和可信赖的。而你会得到一个 InvalidCastException

and your code compiles, but what you are doing is not optimal and trustful at all. And you'll get an InvalidCastException!

编译一个 Expression< T>每个调用的code>并不是最佳的,你怎么知道用户将lambda传递给方法,如:

Compiling an Expression<T> on every call is not optimal, and, how can you tell that the user passes the lambda to the method like:

() => (Id != value)

而不是

() => (id != value) // using the field instead of property

() => (value != Id) // passing the property as the second operand

另外,您的表达式中的不是 ConstantExpression 本身只是属性的集合部分的局部变量,当传递给lambda表达式时,被提升为类字段(该值被捕获 - 请参阅此处更多信息)。那么你所拥有的是一个 MemberExpression 双方。

Also, value in your expression is not a ConstantExpression. The value itself is just a local variable to the set part of the property, and when passed to a lambda expression, is promoted to a class field (the value is captured - see here for more information). So what you have is a MemberExpression on both sides.

我强烈建议您使用这种方法,如果你不能使用.NET 4.5( [CallerMemberName] ):

I highly recommend using this approach if you can't use .NET 4.5 ([CallerMemberName]):

public class EntityBase : INotifyPropertyChanged
{
    protected virtual void OnPropertyChanged(string propName)
    {
        var h = PropertyChanged;
        if (h != null)
            h(this, new PropertyChangedEventArgs(propName));
    }

    public event PropertyChangedEventHandler PropertyChanged;

    protected bool ChangeAndNofity<T>(ref T field, T value, Expression<Func<T>> memberExpression)
    {
        if (memberExpression == null)
        {
            throw new ArgumentNullException("memberExpression");
        }

        var body = memberExpression.Body as MemberExpression;
        if (body == null)
        {
            throw new ArgumentException("Lambda must return a property.");
        }

        if (EqualityComparer<T>.Default.Equals(field, value))
        {
            return false;
        }

        field = value;
        OnPropertyChanged(body.Member.Name);
        return true;
    }
}

使用它很简单:

public class Person : EntityBase
{
    private int _id;
    public int Id
    {
        get { return _id; }
        set { ChangeAndNofity(ref _id, value, () => Id); }
    }
}

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