如何让幻灯片多张屏幕在Sench触摸 [英] How to have the slide multiple screens in Sench touch
问题描述
我正在开发一个应用程序,其中在表单中单击提交按钮时,应该转到其他屏幕。但是它只是将结果打印在窗口之外,而不是真正进入新的屏幕。我已经对商店进行了硬编码,以确保在启动应用程序时有数据,并且它仍然打印在可视区域之外。
I am developing an application in which when submit button is clicked in the form, it should go to a different screen. However it is just printing the results outside of the window and not really going to a new screen. I have hardcoded the store to make sure there is data when I start the application and it still prints it outside of the viewable area.
这是我的Ext.data.Store:
Here is my Ext.data.Store:
var store = new Ext.data.Store({
model: 'jobSummary',
storeId: 'jobStore',
data : [{title: 'This is test'},
{title: 'This is test2'},
{title: 'This is test3'}]
});
以下是我正在使用的列表:
Here is the list that I am using it in:
SearchJobsForm.jobsList = Ext.extend(Ext.Panel, {
dockedItems : [ {
xtype : 'toolbar',
title : 'WTJ',
dock : 'top',
items : [ {
xtype : 'button',
text : 'Back',
ui : 'back',
handler : function() {
//back button controller
},
scope : this
} ]
} ],
items : [ {
xtype : 'list',
emptyText : 'No data available.',
store : 'jobStore',
itemTpl : '<div class="list-item-title">{title}</div>'
+
'<div class="list-item-narrative">{narrative}</div>',
onItemDisclosure : function(record) {
},
grouped : false,
scroll : 'vertical',
fullscreen : true
} ],
initComponent : function() {
SearchJobsForm.jobsList.superclass.initComponent.apply(this, arguments);
}
});
我从我的提交按钮处理程序中调用此列表面板,它是:
And i am calling this list panel from my submit button handler which is:
var jobsList = new SearchJobsForm.jobsList();
我已经粘贴在此链接上的完整代码,以获得更好的可见性:
http://pastebin.com/a05AcvWZ
The full code I have pasted on this link for better visibility: http://pastebin.com/a05AcVWZ
推荐答案
Ok,
SearchJobsForm.form 是你的主面板,它将包含两个组件,一个 searchForm (带文本/选择输入)和面板/结果列表。
在回调中,我们将隐藏()窗体并显示()结果列表。这不是一个干净的代码,而是我可以从你的最简单和最亲密的代码。
SearchJobsForm.form is your main panel, it will contains two components a searchForm (with text/select input) and a panel/list of results. In the callback, we will hide() the form and show() the results list. This is not a clean code, but the simpliest and kissest one I can get from yours.
- 首先让我们实例化jobList
//它的id(id:'jobsListId')
// It has the id ( id: 'jobsListId')
var jobsList = new SearchJobsForm.jobsList();
- 那么你应该把所有的输入都放在一个表单中(xtype:formpanel ,
id:'searchFormId') - 在表单
这里是代码
SearchJobsForm.form = Ext.extend(Ext.Panel,{
initComponent: function(){
Ext.apply(this, {
id: 'searchForm',
floating: true,
width: 250,
height: 370,
scroll: 'vertical',
centered: true,
modal: true,
hideOnMaskTap: false,
items: [
{
xtype: 'formpanel', // 1. this is the added formpanel
itemId: 'searchForm',
id: 'searchFormId', // this id is important
items: [
{
xtype: 'textfield',
...
}, {
xtype: 'textfield',
...
},
// all your inputs
]
},
// 2. add here the results panel : jobsList
jobsList
], // the code continues inchanged
dockedItems: [{
...
- 最后我们将修改ajax回调隐藏/显示面板。不要删除其中的一个,其他地方您将无法重置您的表单
- Finally we will modify the ajax callback to hide/show the panels. Do not remove one of them, elsewhere you won't be able to reset your form
//这里它来
Ext.util.JSONP.request({
url: "http://"+serverAdd+":"+ port+"/users/searchresults.json",
format: 'json',
callbackKey: 'callback',
params : searchCriteria,
callback: function(data) {
console.log('callback');
// Call your list-filling fonctions here
// jobsList.fill(data);
Ext.getCmp('searchFormId').hide();
Ext.getCmp('jobsListId').show();
},
failure: function ( result) {
console.error('Failed');
}
});
对于您的下一个项目,我建议您使用类和命名空间来避免1000个内衬文件; Ext.ns()是你最好的朋友,会避免你头疼很多。
For your next projects, I recommend you to work with classes and namespaces to avoid 1000 lined files ; Ext.ns() is your best friend and will avoid you a lot of headaches.
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