extjs - 当响应不是json时如何提交表单？ [英] extjs - How to submit a form when the response is not json?

问题描述

我明白当我提交表单时，根据文档 ExtJs默认情况下解析响应为JSON。

I understand that when I submit a form, according to the documentation ExtJs by default parses the response as JSON.

在我的情况下，服务器返回HTML，我想显示在一个小组。当我使用 getForm（）。submit（）提交时，ExtJs会抛出一个有关无效JSON的错误：

In my case, the server returns HTML, that I want to display in a Panel. When I submit the from using getForm().submit(), ExtJs will throw an error about invalid JSON:

Ext.JSON.decode(): You're trying to decode an invalid JSON String

如何告诉ExtJs不尝试解析响应？我可以使用响应对象。

How can I tell ExtJs not to attempt to parse the response ? I could the access the text with the response object.

推荐答案

最后，我不可能去工作 form.submit（）的ExtJs。我需要使用 Ext 实现。而且由于这是我应用程序中频繁的模式，所以重要的是要有一个简单的解决方案。

Finally, it was impossible for me to get to work the form.submit() of ExtJs. I needed an implementation using Ext. And since this is a frequent pattern in my application, it is important to have a short an simple solution.

这是我终于找到的（我有一个包含窗体的模态窗口）：

This is what I finally found (I have a modal window containing the form):

var values = me.up('form').getValues(),
panel = Ext.create('My.view.MyPanel', {
    xtype: 'panel',
    loader: {
        url: Paths.ajax + 'sav_vpc/douane.php',
        method: 'get',
        params: values,
        autoLoad: true
    }
});
me.up('window').close()

此解决方案具有另一个优势通过 me.up（'form'）。getForm（）。submit（）解决方案：

This solution has another advantage over the me.up('form').getForm().submit() solution:

code> .getForm（）。submit（）是异步的， .getValues（）是同步的。因此，可以立即关闭窗口。

While .getForm().submit() is asynchronous, .getValues() is synchronous. Therefore, it is possible to close the window immediately.

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