WebDriver查找元素不包含属性 [英] WebDriver find Element not containing attribute

问题描述

我有以下HTML

<button class="x-btn-text " style="position: relative; width: 69px;" type="button" tabindex="0" aria-disabled="false">OK</button>
<button class="x-btn-text" style="position: relative; width: 69px;" type="button" tabindex="0">OK</button>

第一个按钮被禁用，第二个按钮被启用，因为我想点击启用的按钮。有没有办法可以找到元素，没有属性 aria-disabled ？

The first button is disabled and the second button is enabled, since I want to click on the enabled button. Is there a way I could find the element, that doesn't have attribute aria-disabled?

推荐答案

ExtJs案例。在这里，您需要确定是否通过属性 aria-disabled =false使用 getAttribute（aria-disabled）或XPath / CssSelector。

ExtJs case. Here you need determine if it's enabled or not by attribute aria-disabled="false" using getAttribute("aria-disabled") or XPath/CssSelector.

所以代码热心的逻辑应该是正确的，但是ExtJS总是特别的。

So Code Enthusiastic's logic should be correct, however ExtJS is always special on something.

List<WebElement> okButtons = driver.findElements(By.xpath("//button[text() = 'OK']"));
for (WebElement okButton : okButtons) { 
    if (!okButton.getAttribute("aria-disabled").equals("false")) {
        okButton.click();
        break;
    }
}

或者更容易，排除您启用的定位。 （因为你需要在这里文本，所以没有合适的定位器使用CssSelector，只有XPath）

Or even easier, rule out the enabled one in your locator. (As you need to text here, so no suitable locator using CssSelector, only XPath)

WebElement enabledokButton = driver.findElement(By.xpath("//button[text() = 'OK' and not(@aria-disabled = 'false')]"));
enabledokButton.click();

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