Facebook API注册用户 - 错误100：无效的电子邮件散列 [英] Facebook API registerUsers - Error 100: Invalid email hash
问题描述
使用PyFacebook我正在尝试通过我的Facebook应用程序注册我的网站的测试用户。我可以连接到API，并返回朋友列表等。但是，当尝试使用以下方式注册地址时：
Using PyFacebook I am trying to register a test user of my site with my facebook application. I can connect to the API fine and return a list of friends etc. However when trying to register an address using:
hashed_emails = facebook.hash_email('foo@bar.com')
accounts = [hashed_emails]
facebook.connect.registerUsers(accounts)
我得到：
FacebookError：错误100：无效
电子邮件哈希指定当尝试
使用connect.registerUsers（accounts）
FacebookError: Error 100: Invalid email hash specified when trying to use connect.registerUsers(accounts)
然而我知道散列是正确的，作为测试哈希文件返回相同的结果：
Yet I know the hash is correct as the test hash in the documentation returns the same result:
mary@example.com = 4228600737_c96da02bba97aedfd26136e980ae3761
我也知道使用的电子邮件地址绝对是Facebook用户。此外，connect.getUnconnectedFriendsCount（）可以正常运行并返回预期的结果（0！） - 建议指向应用程序的链接可以。
I also know the email address used is definitely a Facebook user. Moreover connect.getUnconnectedFriendsCount() works fine and returns the expected result (0!) - suggesting the link to the App is OK.
发生了什么？ connect.registerUsers（）只有在被授予权限才能使用Friend Linking的情况下才会有效？或者是错误信息我正在收到一些不同的结果捕获全部？或者我只是误解了使用connect.registerUsers（）？
What's going on? Is connect.registerUsers() something that would only work once I've been given 'permission' to use Friend Linking? Or is the error message I'm receiving a catch all for a number of different results? Or have I just misunderstood the use of connect.registerUsers()?
推荐答案
我对API的请求数组格式不正确。应该是：
My request array to the API was incorrectly formatted. It should have been:
hashed_emails = facebook.hash_email('foo@bar.com')
# Wrong: accounts = [hashed_emails]
accounts = [{"email_hash": hashed_emails}]
facebook.connect.registerUsers(accounts)
哪个返回了预期的响应（已注册的哈希表），并被connect.getUnconnectedFriendsCount（）进一步验证，现在返回1.
Which returned the expected response (list of registered hashes) and was further proven by connect.getUnconnectedFriendsCount() which now returns 1.
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