从ffmpeg -i获取视频维度 [英] Getting video dimension from ffmpeg -i

问题描述

如何从 ffmpeg 的信息输出中获取视频的高度和宽度。例如，使用以下输出 -

How would I get the height and width of a video from ffmpeg's information output. For example, with the following output --

$ ffmpeg -i 1video.mp4
...

Input #0, mov,mp4,m4a,3gp,3g2,mj2, from '/Users/david/Desktop/1video.mp4':
  Metadata:
    major_brand     : isom
    minor_version   : 1
    compatible_brands: isomavc1
    creation_time   : 2010-01-24 00:55:16
  Duration: 00:00:35.08, start: 0.000000, bitrate: 354 kb/s
    Stream #0.0(und): Video: h264 (High), yuv420p, 640x360 [PAR 1:1 DAR 16:9], 597 kb/s, 25 fps, 25 tbr, 25k tbn, 50 tbc
    Metadata:
      creation_time   : 2010-01-24 00:55:16
    Stream #0.1(und): Audio: aac, 44100 Hz, stereo, s16, 109 kb/s
    Metadata:
      creation_time   : 2010-01-24 00:55:17
At least one output file must be specified

如何获得 height = 640，width = 360 ？谢谢。

推荐答案

看看 mediainfo 处理大多数格式。

如果您要寻找解析ffmpeg输出的方法，请使用regexp \d + x\d +

If you looking for a way to parse the output from ffmpeg, use the regexp \d+x\d+

使用perl的示例：

$ ./ffmpeg -i test020.3gp 2>&1 | perl -lane 'print $1 if /(\d+x\d+)/'
176x120

使用python（不完美）的示例：

Example using python (not perfect):

$ ./ffmpeg -i /nfshome/enilfre/pub/test020.3gp 2>&1 | python -c "import sys,re;[sys.stdout.write(str(re.findall(r'(\d+x\d+)', line))) for line in sys.stdin]"

[] [] [] [] [] [] [] [] [] [] [] [ ] [] [] [] [] [] [] [] [] ['176x120'] [] [] []

[][][][][][][][][][][][][][][][][][][]['176x120'][][][]

Python one-liners不那么引人入胜作为perl： - ）

Python one-liners aren't as catchy as perl ones :-)

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