HTTP请求与file_get_contents,获取响应代码 [英] HTTP requests with file_get_contents, getting the response code
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问题描述
我正在尝试使用 file_get_contents
连同 stream_context_create
进行POST请求。我的代码到目前为止:
I'm trying to use file_get_contents
together with stream_context_create
to make POST requests. My code so far:
$options = array('http' => array(
'method' => 'POST',
'content' => $data,
'header' =>
"Content-Type: text/plain\r\n" .
"Content-Length: " . strlen($data) . "\r\n"
));
$context = stream_context_create($options);
$response = file_get_contents($url, false, $context);
它工作正常,但是当发生HTTP错误时,会发出警告:
It works fine, however, when an HTTP error occurs, it spits out a warning:
file_get_contents(...): failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request
并返回false。有没有办法:
and returns false. Is there a way to:
- 禁止警告(如果发生故障,我打算抛出自己的异常)
- 从流中获取错误信息(至少是响应代码)
我知道如何做这个卷曲,我的问题具体是关于流/文件功能。
I know how to do that with curl, my question is specifically about stream/file functions.
对不起,如果这是rtm,流的东西对我来说是新的。
Sorry if this is rtm, the streams stuff is new to me.
推荐答案
http ://php.net/manual/en/reserved.variables.httpresponseheader.php
file_get_contents("http://example.com");
var_dump($http_response_header);
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