使用输入文件类型编辑图像 [英] editing image by using input file type

问题描述

我做了一个简单的编辑来编辑mysql中的数据，除了当我想编辑一个输入文件类型的图像时它不工作，一切正常，它不会给出错误消息，它只是不编辑任何东西当我删除输入文件类型的图像它的作品。
和通过编辑图像我的意思是进入一个新的形象将取代旧的形象。

这里是我的代码：

 <？php 
 
 require（db.php）; 
 
 $ id = $ _REQUEST ['theId']; 
 $ result = mysql_query（SELECT * FROM table WHERE id ='$ id'）; 
 $ test = mysql_fetch_array（$ result）; 
 
 $ name = $ test ['Name']; 
 $ email = $ test ['Email']; 
 $ image = $ test ['Image']; 
 
 if（isset（$ _ POST ['submit']））
 {
 $ name_save = $ _POST ['name']; 
 $ email_save = $ _POST ['email']; 
 
 if（isset（$ _ FILES ['image'] ['tmp_name']））
 {
 $ file = $ _FILES ['image'] ['tmp_name'] ; 
 $ image = addslashes（file_get_contents（$ _ FILES ['image'] ['tmp_name']））; 
 $ image_name = addslashes（$ _ FILES ['image'] ['name']）; 
 $ b move_uploaded_file（$ _ FILES [image] [tmp_name]，photos /。$ _FILES [image] [name]）; 
 $ image_save =照片/。 $ _FILES [ 形象] [ 名称]; 
 $ b $ mysql_query（UPDATE table SET Name ='$ name_save'，Email ='$ email_save'，Image ='$ image_save'WHERE id ='$ id'）或die（mysql_error（）） ; 
 
 header（Location：index.php）; 
} 
} 
？> 
 
 
 
< form method =post> 
< table> 
< tr> 
< td>名称：< / td> 
< td> 
< input type =textname =namevalue =<？php echo $ name？>/> 
< / td> 
< / tr> 
< tr> 
< td>电子邮件< / td> 
< td> 
< input type =textname =emailvalue =<？php echo $ email？>/> 
< / td> 
< / tr> 
< tr> 
< td>图片< / td> 
< td> 
< input type =filename =imagevalue =<？php echo $ image？>/> 
< / td> 
< / tr> 
< tr> 
< td>& nbsp;< / td> 
< td> 
< input type =submitname =submitvalue =submit/> 
< / td> 
< / tr> 
< / table> 
  

解决方案

enctype =multipart / form-data在你的表单中没有type =file。

给出下面的代码并尝试。

 <？php 
 require（db.php）; 
 $ id = $ _ REQUEST ['theId']; 
 
 $ result = mysql_query（SELECT * FROM table WHERE id ='$ id'）; 
 $ test = mysql_fetch_array（$ result）; 
 
 $ name = $ test ['Name']; 
 $ email = $ test ['Email']; 
 $ image = $ test ['Image']; 
 
 if（isset（$ _ POST ['submit']））{
 $ name_save = $ _POST ['name']; 
 $ email_save = $ _POST ['email']; 
 $ image_save = $ image //如果图像没有从表单中选择，添加
 
 if（isset（$ _ FILES ['image'] ['tmp_name']））{
 $ file = $ _ FILES ['image'] ['tmp_name']; 
 $ image = addslashes（file_get_contents（$ _ FILES ['image'] ['tmp_name']））; 
 $ image_name = addslashes（$ _ FILES ['image'] ['name']）; 
 move_uploaded_file（$ _ FILES [image] [tmp_name]，photos /。$ _FILES [image] [name]）; 
 $ image_save =照片/。 $ _FILES [ 形象] [ 名称]; 
} 
 mysql_query（UPDATE table SET Name ='$ name_save'，Email ='$ email_save'，Image ='$ image_save'WHERE id ='$ id'）
 or die （mysql_error（））; 
 header（Location：index.php）; } 
？> 
 
 
 
< form method =postenctype =multipart / form-data> 
< table> 
< tr> 
< td>名称：< / td> 
< td>< input type =textname =namevalue =<？php echo $ name？>/>< / td> 
< / tr> 
< tr> 
< td>电子邮件< / td> 
< td>< input type =textname =emailvalue =<？php echo $ email？>/>< / td> 
< / tr> 
 
< tr> 
< td>图片< / td> 
< td>< input type =filename =image/>< / td> 
< / tr> 
< tr> 
< td>& nbsp;< / td> 
< td>< input type =submitname =submitvalue =submit/>< / td> 
< / tr> 
< / table> 
  

此外，如果在更新时未选择图像，则应通过sql和update获取以前的图像值。 / p>

I made a simple editing for to edit data in mysql, everything works fine except when I want to edit an input file type image it doesn't work, it doesn't give an error message it just doesn't edit anything and when I remove the input file type image it works. and by editing an image I mean entering a new image the will replace the old image.

here is my code:

<?php

require("db.php");

$id     = $_REQUEST['theId'];
$result = mysql_query("SELECT * FROM table WHERE id  = '$id'");
$test   = mysql_fetch_array($result);

$name   = $test['Name'] ;
$email  = $test['Email'] ;                  
$image  = $test['Image'] ;

if (isset($_POST['submit']))
{   
    $name_save  = $_POST['name'];
    $email_save = $_POST['email'];

    if (isset($_FILES['image']['tmp_name']))
    {
        $file       = $_FILES['image']['tmp_name'];
        $image      = addslashes(file_get_contents($_FILES['image']['tmp_name']));
        $image_name = addslashes($_FILES['image']['name']);

        move_uploaded_file($_FILES["image"]["tmp_name"],"photos/" . $_FILES["image"]["name"]);
        $image_save ="photos/" . $_FILES["image"]["name"];

        mysql_query("UPDATE table SET Name ='$name_save', Email  ='$email_save',Image ='$image_save' WHERE id = '$id'") or die(mysql_error()); 

        header("Location: index.php");
    }
}
?>



<form method="post">
    <table>
        <tr>
            <td>name:</td>
            <td>
                <input type="text" name="name" value="<?php echo $name ?>"/>
            </td>
        </tr>
        <tr>
            <td>email</td>
            <td>
                <input type="text" name="email" value="<?php echo $email ?>"/>
            </td>
        </tr>
        <tr>
            <td>image</td>
            <td>
                <input type="file" name="image" value="<?php echo $image ?>"/>
            </td>
        </tr>
        <tr>
            <td>&nbsp;</td>
            <td>
                <input type="submit" name="submit" value="submit" />
            </td>
        </tr>
    </table>

解决方案

In form enctype="multipart/form-data" is missing and in your form there is no type="file".

Give the below code and try.

<?php
require("db.php");
$id =$_REQUEST['theId'];

$result = mysql_query("SELECT * FROM table WHERE id  = '$id'");
$test = mysql_fetch_array($result);

$name=$test['Name'] ;
$email= $test['Email'] ;                    
$image=$test['Image'] ;

if(isset($_POST['submit'])){    
$name_save = $_POST['name'];
$email_save = $_POST['email'];
$image_save=$image //Added if image is not chose from the form post

if (isset($_FILES['image']['tmp_name'])) {
$file=$_FILES['image']['tmp_name'];
$image= addslashes(file_get_contents($_FILES['image']['tmp_name']));
$image_name= addslashes($_FILES['image']['name']);
move_uploaded_file($_FILES["image"]["tmp_name"],"photos/" . $_FILES["image"]["name"]);
$image_save ="photos/" . $_FILES["image"]["name"];
}
mysql_query("UPDATE table SET Name ='$name_save', Email  ='$email_save',Image ='$image_save' WHERE id = '$id'")
or die(mysql_error()); 
header("Location: index.php");      }
?>



<form method="post" enctype="multipart/form-data">
<table>
<tr>
<td>name:</td>
<td><input type="text" name="name" value="<?php echo $name ?>"/></td>
</tr>
<tr>
<td>email</td>
<td><input type="text" name="email" value="<?php echo $email ?>"/></td>
</tr>

<tr>
<td>image</td>
<td><input type="file" name="image" /></td>
</tr>
<tr>
<td>&nbsp;</td>
<td><input type="submit" name="submit" value="submit" /></td>
</tr>
</table>

Moreover you should get the previous image value through sql and update if image is not chose while updating.

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