使用PHP从URL字符串获取文件路径/扩展 [英] Use PHP to Get File Path/Extension from URL string

问题描述

我正在阅读 pathinfo basename 之类的东西。但我从这些收集的是如何获得我想要的细节，当使用绝对/相对路径。我想弄清楚的是，我怎样才能从一个url字符串（不一定是活动的URL，也许是一个用户输入url）获取 filename.ext 。

目前我正在寻找获取包含图像的用户提供的URL的文件名和扩展名。但可能想要进一步延伸这一路。所以我想弄清楚如何得到文件名和扩展名。

我想过要使用一些 preg_match 逻辑找到最后/在网址中，分裂它，找到？从那里（如果有的话），并删除超过这一点，然后试图解决什么剩下。但是如果文件中有多个。，例如： 2012.01.01-name.jpg

所以我正在寻找一个完美的方法来做到这一点，而不会有太大的误差。解决方案

使用 parse_url（$ url，PHP_URL_PATH） 来获取URI并在pathinfo / basename中使用URI。

I'm reading up on pathinfo basename and the like. But all I am gathering from those are how to obtain the details I want when using an absolute/relative path. What I am trying to figure out is how can I get the filename.ext from a url string (not necessarily the active URL, maybe a user input url).

Currently I am looking to get the file name and extension of user provided URLs containing images. But may want to extend this further down the road. So in all I would like to figure out how I can get the filename and extension

I thought about trying to use some preg_match logic finding the last / in the url, spliting it, finding the ? from that (if any) and removing the point beyond that and then trying to sort it out after with whats left. but I get stuck in cases where the file has multiple . in the name ie: 2012.01.01-name.jpg

So I am looking for a sane optimal way of doing this without to much margin of error.

解决方案

use parse_url($url, PHP_URL_PATH) to get URI and use URI in pathinfo/basename.

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