番石榴，Files.readLines（）和白色空间 [英] Guava, Files.readLines() and white space

问题描述

  List< String>下面的代码使用了Guava的Files.readLines strings = Lists.newArrayList（）; 
 final File file = new File（filePath）; 
 if（file.isFile（））{
 try {
 strings = Files.readLines（file，Charsets.UTF_8）; 
 
 catch（IOException ioe）{} 
} 
 else {
 //文件不存在
} 
  
一旦我有我的字符串列表我想测试，看看我正在看的当前字符串是在文件中。 
 字符串myString =foo; 
 if（strings.contains（myString））{
 //做某事
} 
  
然而，我想让代码容忍原始文件包含前导或尾随空格（即foo）。
 
 
 
实现这一目标的最优雅的方法是什么？  解决方案

我能想到的tskuzzy的方法如下：

  List< String> trimmedLines = Files.readLines（File，Charsets.UTF_8，
）LineProcessor< List< String>>（）{
 List< String> result = Lists.newArrayList（）; 
 
 public boolean processLine（String line）{
 result.add（line.trim（））; 
} 
 public List< String> getResult（）{return result;} 
}）; 
  

I have the following code which utilises Guava's Files.readLines() method:

List<String> strings = Lists.newArrayList();
final File file = new File(filePath);
if (file.isFile()) {
  try {
    strings= Files.readLines(file, Charsets.UTF_8);
  }
  catch (IOException ioe) {}
}
else {
  // File does not exist
}

Once I have my List of String I'd like to test to see if a current String which I am looking at was in the file.

String myString = "foo";
if (strings.contains(myString)) {
  // Do something
}

However, I'd like to make the code tolerant to the original file contain leading or trailing spaces (i.e. " foo ").

What is the most elegant way of achieving this?

解决方案

The only alternative to tskuzzy's approach that I can think of is as follows:

List<String> trimmedLines = Files.readLines(file, Charsets.UTF_8,
  new LineProcessor<List<String>>() {
    List<String> result = Lists.newArrayList();

    public boolean processLine(String line) {
      result.add(line.trim());
    }
    public List<String> getResult() {return result;}
  });

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