从Windows和Linux读取文件 [英] read file from windows and linux from java

问题描述

我有一个位于 D：\XML\RequestXML 中的xml文件，我正在从 FileReader 。在我的程序中，我硬编码了文件路径 / XML / RequestXML / 。这对 windows 环境可以正常工作。在windows JBoss 中 D：\ jbossdistrib \jboss 。

我在 linux / usr / XML / RequestXML / 中创建了文件夹结构。并将xml添加到RequestXML文件夹中。 JBoss 位于 / usr / jbossdistrib / jboss / 路径中。

如果我将文件路径更改为，那么我们的应用程序就无法在/ XML / RequestXML / / usr / XML / RequestXML / 它可以在linux中运行。

如何在Linux和Windows中使用一致的文件路径？公共类控制器扩展HttpServlet {

私有字符串filePath =/ XML / RequestXML /; $ p

  
 $ b保护void doPost（HttpServletRequest请求，
 HttpServletResponse响应）抛出ServletException，IOException {
 
 String file = request.getParameter（fileName）; 
 
 xml = readFile（filePath + file）; 
 
 
 $ b private String readFile（String file）{
 StringBuffer fileData = new StringBuffer（）; 
 try {
 
 BufferedReader reader = new BufferedReader（new FileReader（file））; 
 char [] buf = new char [1024]; 
 int numRead = 0; （（numRead = reader.read（buf））！= -1）{
 String readData = String.valueOf（buf，0，numRead）; 
 $ b $ 
 fileData.append（readData）; 
 buf = new char [1024]; 
} 
 reader.close（）; 
 
 $ b catch（FileNotFoundException e）{
 logger.fatal（在指定路径中找不到文件+文件）; 
 
 catch（IOException e）{
 logger.fatal（读取xml文件时出错）; 
} 
 return fileData.toString（）; 
 
 
 
 
 
 
 
更新
 
 
 
我的问题是如何在没有 / usr / 的情况下设置文件路径，这在Windows中可以正常工作。 
如果这是不可能的，那么我是否需要在Windows环境中使用路径 / usr / XML / RequestXML / ？所以我必须在Windows中创建一个像 D：\usr\XML\RequestXML 的文件夹结构。
解决方案
如果您知道当前的工作目录（测试它：
 
 
  System.out .println（new File（。）。getAbsolutePath（））; 
  
目录像../../ XML / RequestXML 
 
 
 
记录：虽然这可能有帮助，但我仍然相信你应该试着用配置参数来解决这个问题，加载它作为类路径中的一个资源。
 
I have a xml file located in D:\XML\RequestXML and I am reading xml file in this folder from a FileReader. In my program I hard coded the file path /XML/RequestXML/. This works fine with the windows environment. In windows JBoss is in D:\jbossdistrib\jboss.

I created the folder structure in linux /usr/XML/RequestXML/. And add the xml in to RequestXML folder.  JBoss is in /usr/jbossdistrib/jboss/ path.

But my application can not find the file specified in /XML/RequestXML/  in linux environment.

If I change the file path as /usr/XML/RequestXML/ it works in linux.

How can I use the consistent file path in linux and windows both?
public class Controller extends HttpServlet {

  private String filePath = "/XML/RequestXML/";

  protected void doPost(HttpServletRequest request,
        HttpServletResponse response) throws ServletException, IOException {

       String file = request.getParameter("fileName");

       xml =  readFile(filePath + file);

    }

  private String readFile(String file) {
    StringBuffer fileData = new StringBuffer();
    try {

        BufferedReader reader = new BufferedReader(new FileReader(file));
        char[] buf = new char[1024];
        int numRead=0;

        while((numRead=reader.read(buf)) != -1){
            String readData = String.valueOf(buf, 0, numRead);
            fileData.append(readData);
            buf = new char[1024];
        }
        reader.close();

    }
    catch (FileNotFoundException e) {
        logger.fatal("File not found in specifid path "+ file);
    }
    catch (IOException e) {
        logger.fatal("Error while reading the xml file");
    }
    return fileData.toString();
 }
}




Update

My question is how to set the file path without /usr/ which works fine in Windows. 
If this is not possible, then do I need to use the path as /usr/XML/RequestXML/ in windows environment as well? so I have to create a folder structure like D:\usr\XML\RequestXML in windows.
解决方案
If you know the current working directory  (test it with: 
System.out.println(new File(".").getAbsolutePath());
you can hardcode a relative directory like ../../XML/RequestXML

For the record: although this may help, I still believe you should try to solve this with a configuration parameter or by loading it as a resource available in the classpath.

                        
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