如何在python中递归地生成目录大小，比如du。呢？ [英] How to generate directory size recursively in python, like du . does?

问题描述

可以说我的结构是这样的

  /  - 在这里
 / one / some / dir 
 / two 
 / three / has / many / leaves 
 / hello / world 
  

$ b $

说/ one / some / dir包含一个500mb大文件，/ three / has / many / >我想为每个目录生成大小，以获得这个输出

$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ one / some / dir 500mb
/ two 0
/ three / has / many / leaved - 400mb
/ three / has / many 800
/ three / has / 800 + someotherbigfilehere

我会如何去做这件事？

解决方案

查看 os.walk 。具体来说，这个文档有一个例子来查找一个目录的大小：

  import os $ b $ os from os.path import加入，取得
的根，dirs，os.walk（'python / Lib / email'）中的文件：
 print root，consumes，
 print sum（getsize（join ，
打印bytes in，len（files），非目录文件
如果'CVS'在dirs中：
 dirs.remove（ 'CVS'）＃不要访问CVS目录
  

这应该很容易修改你的目的。



$ p

这是一个未经测试的版本， pre> 从os.path导入os
导入join，getsize
dirs_dict = {}

我们需要从自下而上，以便一个目录可以轻松
＃访问其子目录的大小。
为os.walk（'python / Lib / email'，topdown = False）中的root，dirs，files，

＃循环遍历这个目录中的每个非目录文件，
size = sum（getsize（join（root，name））为文件中的名字）

＃查看所有的子目录，并从`dirs_dict`中加上它们的大小
subdir_size = sum（dirs_dict [join（root，d）] for d in dirs）

＃将这个目录的大小（加上子目录）存储在一个字典中，所以我们
＃可以访问它后来
my_size = dirs_dict [root] = size + subdir_size

print'％s：％d'％（root，my_size）


Lets say my structure is like this

/-- am here
/one/some/dir
/two
/three/has/many/leaves
/hello/world

and say /one/some/dir contains a big file, 500mb, and /three/has/many/leaves contains a 400mb file in each folder.

I want to generate the size for each directory, to have this output

/ - in total for all
/one/some/dir 500mb
/two 0 
/three/has/many/leaved - 400mb
/three/has/many 800
/three/has/ 800+someotherbigfilehere

How would I go about this?

解决方案

Have a look at os.walk. Specifically, the documentation has an example to find the size of a directory:

import os
from os.path import join, getsize
for root, dirs, files in os.walk('python/Lib/email'):
    print root, "consumes",
    print sum(getsize(join(root, name)) for name in files),
    print "bytes in", len(files), "non-directory files"
    if 'CVS' in dirs:
        dirs.remove('CVS')  # don't visit CVS directories

This should be easy enough to modify for your purposes.

---

Here's an untested version in response to your comment:

import os
from os.path import join, getsize
dirs_dict = {}

#We need to walk the tree from the bottom up so that a directory can have easy
# access to the size of its subdirectories.
for root, dirs, files in os.walk('python/Lib/email',topdown = False):

    # Loop through every non directory file in this directory and sum their sizes
    size = sum(getsize(join(root, name)) for name in files) 

    # Look at all of the subdirectories and add up their sizes from the `dirs_dict`
    subdir_size = sum(dirs_dict[join(root,d)] for d in dirs)

    # store the size of this directory (plus subdirectories) in a dict so we 
    # can access it later
    my_size = dirs_dict[root] = size + subdir_size

    print '%s: %d'%(root,my_size) 

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