多部分上传文件servlet [英] Multi part upload file servlet
问题描述
要浏览并选择要上传的文件,您需要一个< input type =file>
字段。正如 HTML规范所述,您需要使用 POST
方法,表单的enctype属性必须设置为 multipart / form-data
。
< form action =uploadServletmethod =postenctype =multipart / form-data>
< input type =filename =file/>
< input type =submit/>
< / form>
提交这样的表单后,表单数据可以以多部分格式在 HttpServletRequest的#的getInputStream()
。为了测试(!)的目的,你可以使用下面的代码片段读取流:
BufferedReader reader = new BufferedReader(new InputStreamReader .getInputStream()));
for(String line;(line = reader.readLine())!= null;){
System.out.println(line);
$ / code>
然而,您需要解析流字节字节(而不是char字符)。在全新的 Servlet 3.0 API之前,标准的Servlet API没有提供任何内置工具来解析它们。常规表单字段也不是通常的 request.getParameter()
方式,它们包含在多部分表单数据流中。
如果你还没有使用Servlet 3.0(只有不到2个旧的版本),那么你需要自己解析流。解析这样的数据流需要精确的背景知识,以了解多部分表单数据请求是如何指定和构造的。要创建一个完美的多部分分析器,你必须写很多代码。但幸运的是,已有多年的 Apache Commons FileUpload 已经证明了它的稳健性。仔细阅读用户指南和常见问题解答查找代码示例,并学习如何使用它以达到最佳程度(以MSIE考虑!)。
How can I upload files and get other paramaters of a form? I want to handle multi part requests in Java servlet.
To browse and select a file for upload you need a <input type="file">
field in the form. As stated in the HTML specification you need to use the POST
method and the enctype attribute of the form has to be set to multipart/form-data
.
<form action="uploadServlet" method="post" enctype="multipart/form-data">
<input type="file" name="file" />
<input type="submit" />
</form>
After submitting such a form the form data is available in multipart format in the HttpServletRequest#getInputStream()
. For testing(!) purposes you can read the stream using the following snippet:
BufferedReader reader = new BufferedReader(new InputStreamReader(request.getInputStream()));
for (String line; (line = reader.readLine()) != null;) {
System.out.println(line);
}
You however need to parse the stream byte by byte (instead of char by char). Prior to the fresh new Servlet 3.0 API, the standard Servlet API didn't provide any builtin facilities to parse them. The normal form fields are also not available the usual request.getParameter()
way, they are included in the multipart form data stream.
If you're not on Servlet 3.0 yet (which is only bit less than 2 monts old), then you need to parse the stream yourself. Parsing such a stream requires precise background knowledge of how multipart form data requests are specified and structured. To create a perfect multipart parser you'll have to write a lot of code. But fortunately there's the Apache Commons FileUpload which has proven its robustness with years. Carefully read both the User Guide and Frequently Asked Questions to find code examples and learn how to use it to an optimum degree (take MSIE into account!).
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