如何在Android中的原始文件夹中打开文件 [英] How to open a file in raw folder in Android

问题描述

我在使用MultipartEntity，我正在尝试引用原始文件夹中的文件。这里是代码：

pre $ MultipartEntity reqEntity = new MultipartEntity（）;
reqEntity.addPart（new FormBodyPart（file，new FileBody（new File（test.txt））））;


test.txt文件位于我的res / raw文件夹中。当我执行代码时，我得到以下异常：FileNotFoundException：/test.txt：打开失败：ENOENT（没有这样的文件或目录）

任何人都可以帮助我不幸的是，你不能直接创建一个 File 对象。原始文件夹。您需要将其复制或复制到您的SD卡或应用程序的缓存中。

您可以通过这种方式为您的文件检索InputStream

  InputStream in = getResources（）。openRawResource（R.raw.yourfile）; 
 
尝试{
 int count = 0; 
 byte [] bytes = new byte [32768]; 
 StringBuilder builder = new StringBuilder（）; （（count = in.read（bytes，0，32768））> 0）{
 builder.append（new String（bytes，0，count））; 
} 
 
 in.close（）; 
 reqEntity.addPart（new FormBodyPart（file，new StringBody（builder.toString（））））; 
} catch（IOException e）{
 e.printStackTrace（）; 
} 
  

I am usin MultipartEntity and I am trying to refer to the file in the raw folder. Here is the code:

MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart(new FormBodyPart("file", new FileBody(new File("test.txt"))));

The test.txt file is in my res/raw folder. When I execute the code I get the following exception : FileNotFoundException: /test.txt: open failed: ENOENT (No such file or directory)

Can anyone help me with this?

解决方案

Unfortunately you can not create a File object directly from the raw folder. You need to copy it or in your sdcard or inside the application`s cache.

you can retrieve the InputStream for your file this way

    InputStream in = getResources().openRawResource(R.raw.yourfile);

  try {
       int count = 0;
       byte[] bytes = new byte[32768];
       StringBuilder builder = new StringBuilder();
       while ( (count = in.read(bytes,0, 32768)) > 0) {
           builder.append(new String(bytes, 0, count));
       }

       in.close();
       reqEntity.addPart(new FormBodyPart("file", new StringBody(builder.toString())));
   } catch (IOException e) {
       e.printStackTrace();
   }

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