php上传文件功能 [英] php upload file function

查看：110 发布时间：2017/11/7 21:31:47 php file-upload

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问题描述

我试图写一个脚本，通过HTML表单上传文件。
当我点击提交没有反应。

file：upload_form.html

 <！DOCTYPE html PUBLIC -  // W3C // DTD XHTML 1.0 Transitional // ENhttp://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> ; 
< html xmlns =http://www.w3.org/1999/xhtml> 
< head> 
< meta http-equiv =Content-Typecontent =text / html; charset = utf-8/> 
< title>无标题文档< / title> 
< / head> 
< body> 
 
< form action =do_upload.phpmethod =postenctype =multipart / form-data>< / form> 
< p>< strong>要上传的文件< / strong>< / p> 
< p>< input name =img1type =filesize =30/>< / p> 
< p>< input name =submittype =submitvalue =Upolad File/>< / p> 
 
< / body> 
< / html>

file：do_upload.php

<$ p $如果（$ _FILES [img1]！={
@copy（$ _ FILES [img1] [tm_name]，/ tmp）$ p $

<？php 
。$ $ _ $ b或die（不能复制文件）; 
} else {
 die（no file specified）; 
} 
 $> 
 $ b< HTML> 
< head> 
< title>成功文件上传< / title> 
< / head> 
< body> 
 
< h1>成功< / h1> 
< p>您发送了：< ;? echo $ _FILES [img1] [name];？> ;< ;? echo $ _FILES [img1] [size];？> byte MIME类型的MIME类型< ;? echo $ _FILES [img1] [type];？>< / p>

解决方案

 < form action =do_upload.phpmethod =postenctype =multipart / form-data>< / form> 
< p>< strong>要上传的文件< / strong>< / p> 
< p><输入名称=img1type =filesize =30/> ;& LT; / p为H. 
< p>< input name =submittype =submitvalue =Upolad File/>< / p>

到

 < form action =do_upload.phpmethod =postenctype =multipart / form-data> 
< p>< strong>要上传的文件< / strong>< / p> 
< p>< input name =img1type =filesize =30/>< / p> 
< p>< input name =submittype =submitvalue =Upolad File/>< / p> 
< / form>

和

  if（$ _FILES [img1]！={

到

  if（isset（$ _ FILES ['img1']））{

I am trying to write a script which uploads a file via a html form. When I click submit nothing happens.

file: upload_form.html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>

<form action="do_upload.php" method="post" enctype="multipart/form-data"></form>
<p><strong>File to upload</strong></p>
<p><input name="img1" type="file" size="30" /></p>
<p><input name="submit" type="submit" value="Upolad File" /></p>

</body>
</html>

file: do_upload.php

<?php
if ($_FILES[img1] != "" {
    @copy($_FILES[img1] [tm_name], "/tmp" .$_FILES[img1][name])
    or die("couldnt copy the file");
} else {
    die("no file specified");
}
?>

<HTML>
<head>
<title>Successfull File Upload</title>
</head>
<body>

<h1>Success</h1>
<p>You sent: <? echo $_FILES[img1][name]; ?>, a <? echo $_FILES[img1][size]; ?>byte filw with a mime type of <? echo $_FILES[img1][type]; ?></p>

</body>
</HTML>

解决方案

<form action="do_upload.php" method="post" enctype="multipart/form-data"></form>
<p><strong>File to upload</strong></p>
<p><input name="img1" type="file" size="30" /></p>
<p><input name="submit" type="submit" value="Upolad File" /></p>

<form action="do_upload.php" method="post" enctype="multipart/form-data">
<p><strong>File to upload</strong></p>
<p><input name="img1" type="file" size="30" /></p>
<p><input name="submit" type="submit" value="Upolad File" /></p>
</form>

and

if ($_FILES[img1] != "" {

if (isset($_FILES['img1'])) {

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