Unix:删除重复的行而不进行排序 [英] Unix: removing duplicate lines without sorting
问题描述
$ b $ pre $ code $#/ usr / bin / env python
import sys
unique_lines = []
duplicate_lines = []
用于sys.stdin中的行:
if line中的unique_lines:
duplicate_lines.append(line)
否则:
unique_lines.append(line)
sys.stdout.write(line)
#可选地做一些与duplicate_lines
这个简单的功能(uniq,不需要先排序,稳定的排序)必须作为一个简单的UNIX工具使用,不是吗?也许在一个管道中的过滤器的组合?
询问的理由:需要这个功能的系统上,我不能从任何地方执行python
UNIX Bash脚本博客 .htmlrel =noreferrer>建议:
awk'!x [$ 0] ++'
这个命令只是告诉awk要打印哪些行。变量 $ 0
包含一行的全部内容,方括号是数组访问。因此,对于文件的每一行,数组 x
的节点增加,如果该节点的内容不是(!
)以前设置。
I have a utility script in Python:
#!/usr/bin/env python
import sys
unique_lines = []
duplicate_lines = []
for line in sys.stdin:
if line in unique_lines:
duplicate_lines.append(line)
else:
unique_lines.append(line)
sys.stdout.write(line)
# optionally do something with duplicate_lines
This simple functionality (uniq without needing to sort first, stable ordering) must be available as a simple UNIX utility, mustn't it? Maybe a combination of filters in a pipe?
Reason for asking: needing this functionality on a system on which I cannot execute python from anywhere
The UNIX Bash Scripting blog suggests:
awk '!x[$0]++'
This command is simply telling awk which lines to print. The variable $0
holds the entire contents of a line and square brackets are array access. So, for each line of the file, the node of the array x
is incremented and the line printed if the content of that node was not (!
) previously set.
这篇关于Unix:删除重复的行而不进行排序的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!