Swift过滤多个字典键 [英] Swift filter for multiple dictionary keys

问题描述

我正在为我的应用制作搜索栏。我正在使用过滤器方法来获取结果。

字典数组：

  var people = [
 [First：John，Last：Doe]，
 [First：Steve，Last：Jobs]，
 [First：Elon，Last：Musk] 
] 
  

我只能搜索First或Last，但不能同时搜索：

  searchResults = people.filter {
 var string = $ 0 [Last] 
 //或First
 
 string = string？.lowercaseString 
 
 return string！.rangeOfString（searchText.lowercaseString）！= nil 
} 
  

解决方案

一种方法是简单地将两个字段与搜索字符串进行比较：

  var people = [
 [First：JohnMusk，Last：Doe]，
 [First：Steve，Last：Jobs]，
[First：Elon，Last：Musk] 
] 
 
 var searchText =Musk
 
 var searchResults = people.filter {
 var firstName = $ 0 [First] !. lowercaseString 
 var lastName = $ 0 [Last] !. lowercaseString 
 
返回firstName.rangeOfString（searchText.lowercaseString） ！=无
 || lastName.rangeOfString（searchText.lowercaseString）！= nil 
 
} 
  

给我这个结果：

  2015-11-18 18：19：47.691 MyPlayground [36558：7031733]（
 {
 First = JohnMusk; 
 Last = Doe; 
}，
 {
 First = Elon; 
 Last = Musk; 
} 
）
  

我相信这就是你想要的。

I'm making a search bar for my app. I'm using the filter method to get the results. I want to search through multiple keys.

Array of dictionaries:

var people = [
               ["First": "John", "Last": "Doe"],
               ["First": "Steve", "Last": "Jobs"],
               ["First": "Elon", "Last": "Musk"]
             ]

I am only able to search for either "First" or "Last", but not both, with this code:

searchResults = people.filter{
            var string = $0["Last"] 
            // or "First"

            string = string?.lowercaseString

            return string!.rangeOfString(searchText.lowercaseString) != nil
        }

解决方案

One approach would be to simply compare both fields to the search string:

var people = [
    ["First": "JohnMusk", "Last": "Doe"],
    ["First": "Steve", "Last": "Jobs"],
    ["First": "Elon", "Last": "Musk"]
]

var searchText = "Musk"

var searchResults = people.filter{
        var firstName = $0["First"]!.lowercaseString
        var lastName = $0["Last"]!.lowercaseString

       return firstName.rangeOfString(searchText.lowercaseString) != nil
              || lastName.rangeOfString(searchText.lowercaseString) != nil

}

This gives me this result:

2015-11-18 18:19:47.691 MyPlayground[36558:7031733] (
        {
        First = JohnMusk;
        Last = Doe;
    },
        {
        First = Elon;
        Last = Musk;
    }
)

Which I believe is what you want.

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