Numpy：快速找到第一个价值指数 [英] Numpy: find first index of value fast

问题描述

如何在Numpy数组中找到第一次出现的索引号？
速度对我很重要。我对以下答案不感兴趣，因为它们扫描整个数组，并且在发现第一次出现时不停止：

  itemindex = numpy.where（array == item）[0] [0] 
 nonzero（array == item）[0] [0] 
   $ b $是一个函数返回的索引的东西b 
 
注意2：使用C编译的方法比Python循环更受欢迎。 
 
解决方案
是为Numpy 2.0.0计划的功能请求： https://github.com/numpy/ numpy / issues / 2269   
How can I find the index of the first occurrence of a number in a Numpy array?
Speed is important to me. I am not interested in the following answers because they scan the whole array and don't stop when they find the first occurrence:
itemindex = numpy.where(array==item)[0][0]
nonzero(array == item)[0][0]
Note 1: none of the answers from that question seem relevant Is there a Numpy function to return the first index of something in an array?

Note 2: using a C-compiled method is preferred to a Python loop.
解决方案
There is a feature request for this scheduled for Numpy 2.0.0: https://github.com/numpy/numpy/issues/2269

                        
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