在结束之后找到额外的空格/新行?> (php标签) [英] Find extra space / new line after a closing ?> (php tag)
问题描述
我怎样才能轻松找到它?我有1000个(PHP标签)在这个应用程序中的文件和100000行代码。
理想情况下,在一些正则表达式结合使用find grep在unix盒子上运行。
这里的问题是普通的grep不匹配多行。所以,我会安装 pcregrep
并尝试下面的命令:
pcregrep -rMl'\?> [\s\\\
] + \ z'*
这将使用PCRE多行匹配( -M
-r 部分)中的所有文件>部分),并且只列出它们的文件名( -l </ code>部分)。
至于模式,匹配?>>
,后跟1个或多个空格或换行符,接着是文件的结尾 \ z
。我发现,当我在我的文件夹上运行这个文件时,许多PHP文件实际上只有一个换行符。所以你可以把这个正则表达式更新为'\?> [\\\\\\\\\\\\\\\\\\\\\\\]在单个
\\\
字符结束符之上。
od -c filename
打印文件的明确表示,如果您需要检查其确切的字符序列结尾。 So I have a space/new line after a closing ?> (php tag) that is breaking my application.
How can I find it easily I have 1000 of files and 100000 lines of code in this app.
Ideally im after some regex combined with find grep to run on a unix box.
The problem here is normal grep doesn't match multiple lines. So, I would install pcregrep
and try the following command:
pcregrep -rMl '\?>[\s\n]+\z' *
This will match all files in the folder and subfolders (the -r
part) using PCRE multiline match (the -M
part), and only list their filenames (the -l
part).
As for the pattern, well that matches ?>
followed by 1 or more whitespace or newline characters, followed by the end of the file \z
. I found though, when I ran this on my folder, many of the PHP files do in fact end with a single newline. So you can update that regex to be '\?>[\s\n]+\n\z'
to match files with whitespace over and above the single \n
character terminator.
Lastly, you can always use od -c filename
to print unambiguous representation of the file if you need to check its exact character sequence ending.
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