如何在Java中的特定单词之后找到具体的值？ [英] How to find a specific value after a specific word in Java?

问题描述

我从 BufferedReader 中获得了一个文本，我需要在特定的字符串中获得一个特定的值。

这是文字：

  aimtolerance = 1024; 
 model = Araarrow; 
 name =弓箭; 
范围= 450; 
 reloadtime = 3; 
 soundhitclass = arrow; 
 type =弹道; 
 waterexplosionclass =小水爆; 
 weaponvelocity = 750; 
 
 default = 213; 
 fort = 0.25; 
 factory = 0.25; 
 stalwart = 0.25; 
 mechanical = 0.5; 
 naval = 0.5; 
  

我需要获得
default = 和;

这是213

解决方案

 字符串行; （（line = reader.readLine（））！= null）{
 int ind = line.indexOf（default =）; 
 if（ind> = 0）{
 String yourValue = line.substring（ind +default =。length（），line.length（） -  1）.trim（）; // -1删除; 
 ............ 
} 
} 
  

I got a text from a BufferedReader and I need to get a specific value in a specific string.

This is the text:

    aimtolerance = 1024;
    model = Araarrow;
    name = Bow and Arrows;
    range = 450;
    reloadtime = 3;
    soundhitclass = arrow;
    type = Ballistic;
    waterexplosionclass = small water explosion;
    weaponvelocity = 750;

        default = 213;
        fort = 0.25;
        factory = 0.25;
        stalwart = 0.25;
        mechanical = 0.5;
        naval = 0.5;

I need to get the exact number between default = and ;

Which is "213"

解决方案

Something like this....

String line;
while ((line = reader.readLine())!=null) {
   int ind = line.indexOf("default =");
   if (ind >= 0) {
      String yourValue = line.substring(ind+"default =".length(), line.length()-1).trim(); // -1 to remove de ";"
      ............
   }
}

这篇关于如何在Java中的特定单词之后找到具体的值？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！