＆是什么QUOT; | =＆QUOT;意味着？ （管等于运算符） [英] What does "|=" mean? (pipe equal operator)

问题描述

我尝试使用谷歌搜索和堆栈＆NBSP搜索，溢出，但它并没有出现任何结果。我已经看到了这样的开源库code：

I tried searching using Google Search and Stack Overflow, but it didn't show up any results. I have seen this in opensource library code:

Notification notification = new Notification(icon, tickerText, when);
notification.defaults |= Notification.DEFAULT_SOUND;
notification.defaults |= Notification.DEFAULT_VIBRATE;

什么是| =？（管等于运营商）的意思

推荐答案

| = 读取相同的方式 + = 。

notification.defaults |= Notification.DEFAULT_SOUND;

是相同的

notification.defaults = notification.defaults | Notification.DEFAULT_SOUND;

其中， | 是位OR操作符

所有的运营商都在这里参考。

All operators are referenced here.

逐位运算符是因为，作为频繁，这些常量使一个int携带国旗。

A bit-wise operator is used because, as is frequent, those constants enable an int to carry flags.

如果您look那些常量，你会看到，他们是在两个大国：

If you look at those constants, you'll see that they're in powers of two :

public static final int DEFAULT_SOUND = 1;
public static final int DEFAULT_VIBRATE = 2; // is the same than 1<<1 or 10 in binary
public static final int DEFAULT_LIGHTS = 4; // is the same than 1<<2 or 100 in binary

所以，你可以使用逐位或添加标记

So you can use bit-wise OR to add flags

int myFlags = DEFAULT_SOUND | DEFAULT_VIBRATE; // makes 001 | 100, which is 101

所以

myFlags |= DEFAULT_LIGHTS;

只是意味着我们添加一个标志。

simply means we add a flag.

和对称，我们测试的一个标志设置使用＆安培; ：

And symmetrically, we test a flag is set using & :

boolean hasVibrate = (DEFAULT_VIBRATE & myFlags) != 0;

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