Firebase数据库 - 如何在Firebase数据库中更新孩子的特定值 [英] Firebase DB - How to update particular value of child in Firebase Database

问题描述

我想在下面的代码中更新我的显示名称。我如何更新我的显示名称。
我的数据库结构如下：

I want to update my display name in below code. How can I update my displayName. My database structer is as below:

-Users
      -KUanJA9egwmPsJCxXpv

         displayName:"Test Trainer"

         email:"[e-mail]"

         uid: "jRXMsNZHR2exqifnR2rXcceEMxF2"

推荐答案

如果您想更新此用户的显示名称：

If you want to update the displayName of this user:

var db = firebase.database();
db.ref("-Users/-KUanJA9egwmPsJCxXpv/displayName").set("New trainer");

或者，您也可以得到相同的结果：

Alternatively, you can also get the same with:

db.ref("-Users/-KUanJA9egwmPsJCxXpv").update({ displayName: "New trainer" });

但是，您可能不知道用户的ID，在这种情况下您需要查看首先：

But it's likely you don't know the ID of the user, in which case you need to look that up first:

var query db.ref("-Users").orderByKey("uid").equalTo("jRXMsNZHR2exqifnR2rXcceEMxF2");
query.once("child_added", function(snapshot) {
  snapshot.ref.update({ displayName: "New trainer" })
});

对数据结构的最后一点评论是：您似乎在存储用户配置文件，但是将它们存储在一个推送ID下。对于这种类型的结构，我们通常建议您将每个用户存储在他们的UID下：

One final remark on your data structure though: you seem to be storing user profiles, but you're storing them under a push ID. For this type of structure we usually recommend that you store each user under their UID:

-Users
      jRXMsNZHR2exqifnR2rXcceEMxF2
         displayName:"Test Trainer"    
         email:"[e-mail]"

有了这样的结构，你可以删除任何两次存储同一用户的机会。此外，您现在可以更新用户的显示名称而不需要查询：

With such a structure you remove any chance that you're storing the same user twice. Plus, you can now update the user's display name without needing a query:

var currentUser = firebase.auth().currentUser;
db.ref("-Users/"+currentUser.uid).update({ displayName: "New trainer" });

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