如何从FirebaseRecyclerAdapter中排除项目 [英] How to exclude item from a FirebaseRecyclerAdapter

问题描述

我在 populateViewHolder 中有这样的代码：

  public void populateViewHolder（最终CampaignHolder viewHolder，最终Campaign广告系列，final int位置）{
 String k = getRef（position）.getKey（）; 
 ref.child（k）.child（users）。addListenerForSingleValueEvent（new ValueEventListener（）{
 @Override 
 public void onDataChange（DataSnapshot dataSnapshot）{
 if（！ dataSnapshot.hasChild（getUid（）））{
 // Something ... 
} 
} 
 $ b $ @Override 
 public void onCancelled（DatabaseError databaseError ）{
 
} 
}）; 
 // ...将人物视为人物... 
  

我想移除物品如果！dataSnapshot.hasChild（getUid（））是 true，否则继续正常填充ViewHolder。请注意，我不想从数据库中删除项目，我只希望它从 FirebaseRecyclerAdapter 中消失。什么方法可以做到这一点？

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编辑：我仍然在寻找解决方案对于这个问题，因为没有被修复。我的解决方案是非常不鼓励和非常糟糕的做法，我已经重新考虑使用它自己。

解决方案

最佳做法是使用服务器端过滤：
https://firebase.google.com/目前无法用FirebaseUI过滤客户端的结果（不过我相信计划在未来实施）：


https://github.com/firebase/FirebaseUI-Android/issues/135

I have this code in my populateViewHolder:

public void populateViewHolder(final CampaignHolder viewHolder, final Campaign campaign, final int position) {
            String k = getRef(position).getKey();
            ref.child(k).child("users").addListenerForSingleValueEvent(new ValueEventListener() {
                @Override
                public void onDataChange(DataSnapshot dataSnapshot) {
                    if (!dataSnapshot.hasChild(getUid())) {
                       //Something...
                    }
                }

                @Override
                public void onCancelled(DatabaseError databaseError) {

                }
            });
            //...Populating the viewholder...

I want to remove the item if !dataSnapshot.hasChild(getUid()) is true, otherwise just keep on populating the ViewHolder normally. Note that I don't want to remove the item from the database, I only want it gone from the FirebaseRecyclerAdapter. What method is available for doing this?

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Edit: I am STILL looking for a solution for this problem as it has not been fixed. My solution is HIGHLY discouraged and very bad practice, and I have reconsidered using it myself.

解决方案

Best practice would be to use server side filtering: https://firebase.google.com/docs/database/android/retrieve-data#sorting_and_filtering_data

At the moment there is no way to filter your results client side with FirebaseUI (however I do believe it is planned to be implemented in the future):
https://github.com/firebase/FirebaseUI-Android/issues/135

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