通过Firebase动态链接Android传递多个参数 [英] Pass multiple params via Firebase Dynamic links Android

问题描述

我使用了Firebase Dynamics链接，可以打开我的应用，转到商店或转到某个网址。但是当我通过链接传递一些参数时，我只能得到第一个参数。
这是我的动态链接：

  https://xx.app.goo.gl/?link=http： //xx.com/?usn=abc&pass=def&apn=com.xx&afl=http://google.com 
  

我使用这段代码来获取链接：

  //使用AppInvite API构建GoogleApiClient用于接收深层链接
 mGoogleApiClient = new GoogleApiClient.Builder（this）
 .enableAutoManage（this，this）
 .addApi（AppInvite.API）
 .build（）; 
 
 //检查此应用是否从深层链接启动。将autoLaunchDeepLink设置为true 
 //如果找到，则会自动启动深层链接。 
 boolean autoLaunchDeepLink = false; 
 appInvite.AppInviteApi.getInvitation（mGoogleApiClient，this，autoLaunchDeepLink）
 .setResultCallback（
 result  - > {
 if（result.getStatus（）。isSuccess（））{
 //从Intent提取深层链接
 Intent intent = result.getInvitationIntent（）; 
 String deepLink = AppInviteReferral.getDeepLink（intent）; 
 Logger.e（deepLink）; 
} 
} 
）; 
  

和日志打印： http://xx.com/?usn=abc （pass = def已经丢失）
任何人都可以解决这个问题？

解决方案

您需要 URL编码 link 参数的值，否则系统将无法确定动态链接的参数是什么，以及<$ $的子参数是什么这意味着最终的URL看起来像 https：/ / c $ c> link 动态链接的参数。 /xx.app.goo.gl/?link=http%3A%2F%2Fxx.com%2F%3Fusn%3Dabc%26pass%3Ddef&apn=com.xx&afl=http://google.com $ b $ p
$ b

重要提示：如果您（正如我怀疑的那样）试图通过明文链接参数传递用户名和密码，是一个非常糟糕的主意。严重的是， 不要这样做 。阅读这个答案，以获得像这样的要求的正确方法。

I've used Firebase Dynamics link and it can open my app, go to play store or go to an URL. But when I pass some parameters through link, I can only get first parameter. Here's my dynamic links:

https://xx.app.goo.gl/?link=http://xx.com/?usn=abc&pass=def&apn=com.xx&afl=http://google.com

And I used this code to get the link:

// Build GoogleApiClient with AppInvite API for receiving deep links
        mGoogleApiClient = new GoogleApiClient.Builder(this)
                .enableAutoManage(this, this)
                .addApi(AppInvite.API)
                .build();

        // Check if this app was launched from a deep link. Setting autoLaunchDeepLink to true
        // would automatically launch the deep link if one is found.
        boolean autoLaunchDeepLink = false;
        AppInvite.AppInviteApi.getInvitation(mGoogleApiClient, this, autoLaunchDeepLink)
                .setResultCallback(
                        result -> {
                            if (result.getStatus().isSuccess()) {
                                // Extract deep link from Intent
                                Intent intent = result.getInvitationIntent();
                                String deepLink = AppInviteReferral.getDeepLink(intent);
                                Logger.e(deepLink);
                            }
                        }
                );

And the log print: http://xx.com/?usn=abc (the pass=def was lost) Anyone resolve this issue?

解决方案

You need to URL encode the value of the link parameter, otherwise the system can't tell what is a parameter of the Dynamic Link and what is a sub-paramater of the link parameter of the Dynamic Link.

This means the final URL should look like https://xx.app.goo.gl/?link=http%3A%2F%2Fxx.com%2F%3Fusn%3Dabc%26pass%3Ddef&apn=com.xx&afl=http://google.com

Important note: if you are (as I suspect) attempting to pass usernames and passwords through as plaintext link parameters, this is an incredibly bad idea. Seriously, do not do this. Read this answer for the proper approach to a requirement like this.

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