Android Firebase应用多个查询 [英] Android firebase apply multiple queries

问题描述

我有以下资料库：

pre $ -KYTfJZQbg0RVzHeecIS
createdAt：1481204648530
message：rgd
阅读：false
接收者：583d15cf45f3330807364c55
发件人：58490e9945f33364ac6cd7b1
updateAt：1481204648654

现在我要筛选结果READ== FALSE ANDSENDER== 58490e9945f33364ac6cd7b1

我该如何实现


$ b $ p
$ b

编辑： -

我在android中使用它作为

  Query query = reference.orderByChild（read ）.equalTo（false）
 .orderByChild（sender）。equalTo（datum.getEmployer（）。getEmployerId（））; 
  

它给了 java.lang.IllegalArgumentException：不能将多个orderBy调用！

解决方案

不幸的是，这不是直接使用Firebase .....有很好的例子在Firebase家伙下面的视频中做了非常类似的事情（大概9分钟） https://www.youtube.com/watch?v=sKFLI5FOOHs&list=PLl-K7zZEsYLlP-k-RKFa7RyNPa9_wCH2s&index=4

I have following database

-KYTfJZQbg0RVzHeecIS
     createdAt: 1481204648530
     message: "rgd"
     read: false
     reciever: "583d15cf45f3330807364c55"
     sender: "58490e9945f33364ac6cd7b1"
     updateAt: 1481204648654

Now I want to filter the result for "READ"==FALSE AND "SENDER"==58490e9945f33364ac6cd7b1

how can I achieve this?

Any help would be appreciated Thanks

EDIT :-

I am using this in android as

Query query = reference.orderByChild("read").equalTo(false)
                .orderByChild("sender").equalTo(datum.getEmployer().getEmployerId());

it gave java.lang.IllegalArgumentException: You can't combine multiple orderBy calls!

解决方案

Unfortunately this isn't straightforward using Firebase.....there's good example of doing something very similar in following video by Firebase guys (about 9 mins in) https://www.youtube.com/watch?v=sKFLI5FOOHs&list=PLl-K7zZEsYLlP-k-RKFa7RyNPa9_wCH2s&index=4

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