如何阅读RES /原始的名字文件 [英] How to read file from res/raw by name
问题描述
我想打开从文件夹RES /生/文件。 我绝对相信该文件存在。 要打开我试图文件
I want to open a file from the folder res/raw/. I am absolutely sure that the file exists. To open the file I have tried
File ddd = new File("res/raw/example.png");
命令
ddd.exists();
生成FALSE。因此,这种方法是行不通的。
yields FALSE. So this method does not work.
尝试
MyContext.getAssets().open("example.png");
结束了在一个例外的getMessage()空。
ends up in an exception with getMessage() "null".
只需用
R.raw.example
是不可能的,因为文件名是运行作为字符串中唯一已知的。
is not possible because the filename is only known during runtime as a string.
为什么如此难以访问的文件夹/ RES /生/?
Why is it so difficult to access a file in the folder /res/raw/ ?
推荐答案
在给定的链接,我能够解决自己的问题的帮助。正确的方法是,以获得与资源ID
With the help of the given links I was able to solve the problem myself. The correct way is to get the resource ID with
getResources().getIdentifier("raw/FILENAME_WITHOUT_EXTENSION",
"raw", getPackageName());
要得到它作为一个的InputStream
To get it as a InputStream
InputStream ins = getResources().openRawResource(
getResources().getIdentifier("raw/FILENAME_WITHOUT_EXTENSION",
"raw", getPackageName()));
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