Jersey UniformInterfaceException试图代理到REST POST服务 [英] Jersey UniformInterfaceException trying to proxy to REST POST service

问题描述

当我尝试执行以这种方式构建的代码时，我一直收到一个406 HTTP响应。我已经尝试过很多次重构代码和输入，但是我仍然收到这个错误，而且我甚至不知道要调试什么。这个异常似乎表明 post（）方法没有提供所需格式的 @FormParam 但您可以看到 .accept（MediaType.APPLICATION_FORM_URLENCODED）和 @Consumes（MediaType.APPLICATION_FORM_URLENCODED）匹配。

我使用Firefox附加组件 HTTPRequester 传入 @FormParam s，并确保我将它们传入适当的Content-Type（应用程序/ x-WWW窗体-urlencoded ）。我已经用完了检查的东西。有没有人有任何想法？

---

代理服务

 客户端客户端= Client.create（）; 
 WebResource服务= client.resource（myURL）; 
 
 Form form = new Form（）; 
 form.add（value1，value1）; 
 form.add（value2，value2）; 
 form.add（valueN，valueN）; 
 
 String returnValue = service.accept（MediaType.APPLICATION_FORM_URLENCODED）.post（String.class，form）; 
  

实际服务

  @POST 
 @Produces（MediaType.APPLICATION_XML）
 @Consumes（MediaType.APPLICATION_FORM_URLENCODED）
 @Path（/ theService）
 public String theService（
 @FormParam（value1）字符串value1，
 @FormParam（value2）字符串value2，
 @FormParam（valueN）字符串valueN）{ 
 
 String returnValue = null; 
 
 / * 
 *做东西
 * / 
 
 return returnValue; 
 
  

  com.sun.jersey.api.client.UniformInterfaceException：POST http：// theURL / theService在com返回的响应状态为406 
。 sun.jersey.api.client.WebResource.handle（WebResource.java:563）
 at com.sun.jersey.api.client.WebResource.access $ 300（WebResource.java:69）
 at com .sun.jersey.api.client.WebResource $ Builder.post（WebResource.java:499）
  

解决方案

UniformInterfaceException 只是一个不好名称的全部异常（它被命名为这是因为它是一个提供统一接口的异常，不管错误）。这基本上是Jersey中任何东西抛出的IOException。实际的错误是 406无法接受：

所请求的资源只能根据请求中发送的Accept标头生成不可接受的内容。

这里您表示接受 MediaType.APPLICATION_FORM_URLENCODED ：

  String returnValue = service.accept（MediaType.APPLICATION_FORM_URLENCODED）.post（String.class，form）; 
  

但是您的服务产生 MediaType.APPLICATION_XML ：

  @Produces（MediaType.APPLICATION_XML）
  

因为你的服务器不能产生任何客户说它会接受的内容，所以它会返回一个406错误。

，你的意思是设置 WebResource.type ，而不是接受 ：

  String returnValue = service.type（MediaType.APPLICATION_FORM_URLENCODED）.post（String.class，form）; 
  

I keep receiving a 406 HTTP response when I try to execute code structured in this way. I have tried restructuring the code and the inputs many times, but I still receive this error, and I've gotten to the point I don't even really know what to debug. The exception seems to indicate that the post() method isn't supplying the @FormParams in the desired format, but as you can see the .accept(MediaType.APPLICATION_FORM_URLENCODED) and the @Consumes(MediaType.APPLICATION_FORM_URLENCODED) do indeed match up.

I am using the Firefox add-on HTTPRequester to pass in the @FormParams and have ensured that I am passing them in with the appropriate Content-Type (application/x-www-form-urlencoded). I've run out of things to check. Does anyone have any ideas?

---

The Proxy Service

Client client = Client.create();
WebResource service = client.resource(myURL);

Form form = new Form();
form.add("value1", value1);
form.add("value2", value2);
form.add("valueN", valueN);

String returnValue = service.accept(MediaType.APPLICATION_FORM_URLENCODED).post(String.class, form);

The Actual Service

@POST
@Produces(MediaType.APPLICATION_XML)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
@Path("/theService")
public String theService(
        @FormParam("value1") String value1,
        @FormParam("value2") String value2,
        @FormParam("valueN") String valueN) {

    String returnValue = null;

    /*
     * Do Stuff
     */

    return returnValue;
}

The Exception

com.sun.jersey.api.client.UniformInterfaceException: POST http://theURL/theService returned a response status of 406
at com.sun.jersey.api.client.WebResource.handle(WebResource.java:563)
at com.sun.jersey.api.client.WebResource.access$300(WebResource.java:69)
at com.sun.jersey.api.client.WebResource$Builder.post(WebResource.java:499)

解决方案

UniformInterfaceException is just a catch-all exception with a poor name (it's named this because it's an exception that provides a uniform interface, no matter the error). It's basically an IOException thrown by anything in Jersey. The actual error is the 406 Unacceptable:

The requested resource is only capable of generating content not acceptable according to the Accept headers sent in the request.

Here you're saying that you accept MediaType.APPLICATION_FORM_URLENCODED:

String returnValue = service.accept(MediaType.APPLICATION_FORM_URLENCODED).post(String.class, form);

But your service produces MediaType.APPLICATION_XML:

@Produces(MediaType.APPLICATION_XML)

Since your server can't produce any content that the client says it will accept, it returns a 406 error.

Most likely, you're meaning to set WebResource.type, not accept:

String returnValue = service.type(MediaType.APPLICATION_FORM_URLENCODED).post(String.class, form);

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