压缩文件内容没有数据 [英] zip file contents have no data

问题描述

我已经有一段时间试图做一个压缩脚本。
最接近我所需要的就是这个。

  import flash.filesystem.File; 
 import flash.events.Event; 
导入FZIP。*; 
 
 var目录：File = File.desktopDirectory.resolvePath（Test File）; 
 
 var zip：FZip = new FZip（）; 
 var files：Array = directory.getDirectoryListing（）; 
 for（var i：uint = 0; i< files.length; i ++）
 {
 var file_2：File = new File（files [i] .nativePath）; 
 // zip.addFile（file_2.name，file_2.data）; 
 zip.addFile（file_2.name，ba）; 
 trace（file_2.name）; 
 trace（files [i] .nativePath）; 
 trace（file_2.data）; 
 trace（file_2.size）; 
} 
 
 var ba：ByteArray = new ByteArray（）; 
 zip.serialize（ba）; 
 ba.position = 0; 
 var finalZIP：File = File.desktopDirectory.resolvePath（TEST.zip）; 
 var fs：FileStream = new FileStream（）; 
 fs.open（finalZIP，FileMode.WRITE）; 
 fs.writeBytes（ba）; 
 trace（BA POS：+ ba.position）; 
 fs.close（）; 
  

问题是所有文件都没有数据（没有大小）。 $ b

解决方案

我不使用FZIP，但由于你没有答案，我检查了周围，似乎正确的用法是这样的下面（或至少让你更靠近）..

  import flash.filesystem.File; 
 import flash.events.Event; 
导入FZIP。*; 
导入FZIP; 
 
 var目录：File = File.desktopDirectory.resolvePath（Test File）; 
 var files：Array = directory.getDirectoryListing（）; 
 var zip：FZip = new FZip（）; 
 
 var fs：FileStream; 
 var temp_BA：ByteArray = new ByteArray（）; //通用和回收
 
 var fileCount：int = 1; //用于文件计数作为文件名（至少假定1个文件）
 
 var temp_Str：String =; //一个临时的字符串来保存文件的名称，然后将其添加到ZIP 
 var extension_Str：String =; / /设置文件扩展名放置在ZIP 
 
中（var i：uint = 0; i< files.length; i ++）
 {
 //＃迭代FOR循环
 temp_BA.clear（）; fs = new FileStream（）; 
 
＃将文件的字节添加到字节数组
 var file_2：File = new File（files [i] .nativePath）; 
 fs.open（file_2，FileMode.READ）; 
 fs.readBytes（temp_BA）; // temp_BA现在将文件内容保存为字节数组
 //temp_BA.writeBytes（fs）; //比readbytes方法更快如果可以完成
 
 //＃（1）如果你以前的这一行适用于你，保存它
 //zip.addFile(file_2.name ，temp_BA）; // addFile需要内容字节数组和名称
 
 //＃（2）或者像下面这样使用try（1）
 extension_Str =jpg; //或从磁盘上的实际文件扩展名中获取字符串
 temp_Str =file+ String（fileCount）+。 + extension_Str; //例：使temp_Str =file1.jpg
 zip.addFile（temp_Str，temp_BA）; //使ZIP包含一个文件名[temp_Str]&文件数据来自[temp_BA] 
 
 fs.close（）; 
 fileCount ++; //增加一个
} 
 
 // var finalZIP：File = File.desktopDirectory.resolvePath（TEST.zip）; 
 var finalZIP：File = File.applicationStorageDirectory; 
 finalZIP = finalZIP.resolvePath（TEST.zip）; 
 
 var fs：FileStream = new FileStream（）; 
 fs.open（finalZIP，FileMode.WRITE）; 
 zip.serialize（fs）; //生成ZIP文件数据
 fs.close（）; 
  

I have for a while been trying to make a zipping script. The closest I have come to what I am needing is this one.

import flash.filesystem.File;
import flash.events.Event;
import FZIP.*;

var directory:File = File.desktopDirectory.resolvePath("Test File");

var zip:FZip = new FZip(); 
var files:Array = directory.getDirectoryListing();
for(var i:uint = 0; i < files.length; i++)
{
var file_2:File = new File(files[i].nativePath);
//  zip.addFile(file_2.name, file_2.data);
zip.addFile(file_2.name, ba);
trace(file_2.name);
trace(files[i].nativePath);
trace(file_2.data);
trace(file_2.size);
}

var ba:ByteArray = new ByteArray(); 
zip.serialize(ba); 
ba.position = 0; 
var finalZIP:File = File.desktopDirectory.resolvePath("TEST.zip"); 
var fs:FileStream = new FileStream(); 
fs.open(finalZIP, FileMode.WRITE); 
fs.writeBytes(ba); 
trace("BA POS: "+ba.position);
fs.close();

The problem is that all files are without data (have no size).

解决方案

I don't use FZIP but since you got no answer I checked around and it seems the correct usage would be something like this below (or at least get you closer)..

import flash.filesystem.File;
import flash.events.Event;
import FZIP.*;
import FZIP;

var directory:File = File.desktopDirectory.resolvePath("Test File");
var files:Array = directory.getDirectoryListing();
var zip:FZip = new FZip(); 

var fs:FileStream; 
var temp_BA:ByteArray = new ByteArray(); //general use and recycle

var fileCount:int = 1; //for file count as file name (assumes 1 file at least)

var temp_Str:String = ""; // a temp String to hold a file's name before adding it to ZIP
var extension_Str : String = ""; //set file extension placed inside the ZIP

for(var i:uint = 0; i < files.length; i++)
{
    //# reseting for each iteration of the FOR loop
    temp_BA.clear(); fs = new FileStream(); 

    //# add file's bytes into a byte array
    var file_2:File = new File(files[i].nativePath);
    fs.open(file_2, FileMode.READ);
    fs.readBytes( temp_BA ); //temp_BA now holds file content as byte array
    //temp_BA.writeBytes( fs ); //is faster than readbytes method if can be done

    //# (1) If this line you had before works for you, keep it
    //zip.addFile(file_2.name, temp_BA); //addFile needs the content byte array and a name for it

    //# (2) or use try like this below version instead (1) above
    extension_Str = "jpg" ; //or get String from actual file extension on disk
    temp_Str = "file" + String(fileCount) + "." + extension_Str; //eg: makes temp_Str = "file1.jpg"
    zip.addFile( temp_Str, temp_BA); //make ZIP contain a file-name [temp_Str] & file-data is from [temp_BA]

    fs.close();
    fileCount++; //increment by one
}

//var finalZIP:File = File.desktopDirectory.resolvePath("TEST.zip"); 
var finalZIP:File = File.applicationStorageDirectory;
finalZIP = finalZIP.resolvePath("TEST.zip");

var fs:FileStream = new FileStream();
fs.open(finalZIP, FileMode.WRITE);
zip.serialize(fs); //generate ZIP file data
fs.close();

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