为什么Flask应用程序创建两个进程? [英] Why does a Flask app create two process?
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问题描述
即使是最简单的应用程序。
from flask导入Flask $ b $ from flask导入render_template,request,flash ,会话,重定向
app = Flask(__ name__)
@ app.route('/')
def hello_world():
return' Hello World!'
app.run(host =192.168.21.73,port = 5000,debug = True)
你可以看到两个进程正在运行:
ps -x
5026 ttyO0 S + 0:01 / usr / bin / python ./test_flask.py
5031 ttyO0 Sl + 0:45 / usr / bin / python ./test_flask.py
这里发生了什么事情?
解决方案
用reloader重新运行dev服务器。重新加载程序监视文件系统的变化,并在不同的进程启动真正的应用程序,所以有两个总进程。
您可以通过设置<$ c $当调用 run
时,c> debug = False 或 use_reloader = False
。
As far as I understood Flask should create a thread and a second thread to run on it, but what I see is there are always two processes, not threads, running. Even for the simplest app.
from flask import Flask
from flask import render_template, request, flash, session, redirect
app = Flask(__name__)
@app.route('/')
def hello_world():
return 'Hello World!'
app.run(host="192.168.21.73", port=5000, debug=True)
You can see two process running:
ps -x
5026 ttyO0 S+ 0:01 /usr/bin/python ./test_flask.py
5031 ttyO0 Sl+ 0:45 /usr/bin/python ./test_flask.py
What is happening here?
解决方案
It's because you're running the dev server with the reloader. The reloader monitors the filesystem for changes and starts the real app in a different process, so there are two total processes.
You can disable the reloader by settting debug=False
or use_reloader=False
when calling run
.
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