从Flask上下文处理器读取URL变量 [英] Read URL variables from Flask context processor
本文介绍了从Flask上下文处理器读取URL变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
@ app.route('/ post /< int :post_id>')
def show_post(post_id):
return'Post%d'%post_id
现在,我要注册一个上下文处理器,它只在使用<$ c $调用视图函数时才运行
- c> post_id 作为参数
- 以某种方式访问
post_id
,而不必重新解析重新整理网址,例如re.match
本质上:
@ app.context_processor
def foo():
post_id = ???
return {'bar':some_function(post_id)}
如果我可以访问 ** kwargs
在这个例子中传递给 show_post
来自上下文处理器我可以做到这一点,但是我发现没有办法做到这一点。任何想法?
解决方案
使用 request.view_args
:
@ app.context_processor
def provide_foo():$ b $如果request.view_args中的post_id:
post_id = request.view_args [post_id]
return {bar :some_function(post_id)}
Suppose I have a simple route with a variable part:
@app.route('/post/<int:post_id>')
def show_post(post_id):
return 'Post %d' % post_id
Now I want to register a context processor that
- Only runs when the view function is called with
post_id
as a parameter - somehow has access to
post_id
, without having to re-parse the URL all over again with e.g.re.match
essentially:
@app.context_processor
def foo():
post_id = ???
return {'bar': some_function(post_id)}
If I could access the **kwargs
passed to show_post
in this example from the context processor I could do it, but I've found no way to do that. Any ideas?
解决方案
Use request.view_args
:
@app.context_processor
def provide_foo():
if "post_id" in request.view_args:
post_id = request.view_args["post_id"]
return {"bar": some_function(post_id)}
这篇关于从Flask上下文处理器读取URL变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文