如何将任意参数传递给瓶蓝图？ [英] How to pass arbitrary arguments to a flask blueprint?

问题描述

我有一个瓶子，我已经包裹在一个物体。这样做使得单元测试变得轻而易举，因为我可以根据是否在生产，测试或whatehaveyou中，以各种不同的设置来实例化api。

我正在尝试扩展api，为此我使用蓝图。问题是，我无法弄清楚如何将论据传递给蓝图。我的路线需要像访问哪个数据库的信息，而且这些信息不是静态的。我怎样才能将这些信息转化为蓝图？我已经将下面的代码作为例子：

api.py：

  class MyApi（object）：
 def __init __（self，databaseURI）：
 self.app = Flask（__ name__）
 self.app.register_blueprint（myblueprint）
  

blueprint.py



  myblueprint = Blueprint（'myblueprint'，__name__）
 @ myblueprint.route（'/ route'，methods = ['GET']）
 def route（）：
 database = OpenDatabaseConnection（databaseURI ）
  

这里有一个相关的问题：
如何将构造函数参数传递给Flask Blueprint？

但是回答问题的人解决了op的用例特定问题，而没有真正回答如何将任意参数传递给蓝图的问题。

解决方案

<您可以在构造函数中动态地创建蓝图：

  def construct_blueprint（database）：
 
 myblueprint = Blueprint（'myblueprint'，__name__）
 
 @ myblueprint.route（'/ route'，methods = ['GET']）
 def route（）：
 database = database 
 
 return（myblueprint）
  

I have a flask api which I have wrapped up in an object. Doing this has made unit testing a breeze, because I can instantiate the api with a variety of different settings depending on whether it is in production, test, or whatehaveyou.

I am now trying to extend the api a bit, and for that I'm using a blueprint. The problem is that I cannot figure out how to pass arguments to the blueprint. My routes require information like which database to access, and that information is not static. How can I pass this information into a blueprint? I have included code below as an example:

api.py:

class MyApi(object):
    def __init__(self, databaseURI):
     self.app = Flask(__name__)
     self.app.register_blueprint(myblueprint)

blueprint.py

myblueprint= Blueprint('myblueprint', __name__)
@myblueprint.route('/route', methods=['GET'])
def route():
  database = OpenDatabaseConnection(databaseURI)

There is a related question here: How do I pass constructor arguments to a Flask Blueprint?

But the people who answer the question solve the op's use-case specific problem without actually answering the question of how to pass arbitrary arguments to a blueprint.

解决方案

You could create the blueprint dynamically in a constructor function:

def construct_blueprint(database):

    myblueprint = Blueprint('myblueprint', __name__)

    @myblueprint.route('/route', methods=['GET'])
    def route():
        database = database

    return(myblueprint)

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