如何链接到不在静态文件夹中的图像 [英] How do i link to images not in Static folder in flask

问题描述

我现在将用户上传的照片保存在烧录文件夹以外的目录中（在 openshift ，当前保存在 app-root / data 下的数据文件夹中的镜像， code> app-root / repo / ）。

在我的模板中，如何提供图像文件？

使用 url_for ，我如何引用这些位于flask文件夹之外的图像文件？

   -  data / 
 | 
  - 上传/ 
  - 回购/ 
 | 
  -  app / 
 | 
  -  __init__.py 
  

正如您可以看到flask app文件夹外的数据文件夹。如何从flask app目录生成链接到存储在 data / uploads （上一层）中的文件是个问题？

解决方案

您有 send_from_directory

a> 函数可以实现你想要的功能，我要做的就是用媒体文件所在的路径声明一个名为 MEDIA_FOLDER 的常量，然后，唯一需要做的就是调用这样的函数：

$ p $ from config import MEDIA_FOLDER

@ app.route（'/ uploads /< path：filename>'）
def download_file（filename）：
return send_from_directory（MEDIA_FOLDER，filename，as_attachment = True）

$ b然后，调用它，你可以这样做：

pre $ {code $ { {url_for（'download_file'，filename ='dogs.jpg'）}}

有关th的信息此处。

In flask, how do I serve images that are not in the static folder?

I currently save the user uploaded photos on a directory that is outside the flask folder (On openshift, image currently saving in the data folder under app-root/data and the flask files are in app-root/repo/).

In my templates, how do i serve the image files ?

Using url_for, how do i reference these image files that are outside the flask folder?

- data/
 |
  -- uploads/
- repo/
 |
  -- app/
    |
     -- __init__.py

As you can see the data folder outside the flask app folder. How do i generate links to files stored in data/uploads (one level up) from the flask app directory is the question ?

解决方案

You have the send_from_directory function that does what you want, what I would do is declare a constant called MEDIA_FOLDER with the path where the media files are located and then, the only thing you need to do is to call the function like this:

from config import MEDIA_FOLDER

@app.route('/uploads/<path:filename>')
def download_file(filename):
    return send_from_directory(MEDIA_FOLDER, filename, as_attachment=True)

Then, to invoke it, you just do this:

{{ url_for('download_file', filename='dogs.jpg') }}

You can have more info about this here.

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