results = results ['results'] ['bindings']烧瓶错误 [英] results = results['results']['bindings'] Flask error
问题描述
通过这个Sparql入口点: http:// digitale .bncf.firenze.sbn.it / openrdf-workbench / repositories / NS_03_2014 / query
我有错误:TypeError:query()至少2个参数(1给出)
谢谢!!!
pre $ code > @ app.route('/ caricaArgomento /< type>',methods = ['GET'])
def getArgomento(type):
#sparql = SPARQLUpdateStore(http:// digitale。 bncf.firenze.sbn.it/openrdf- workbench / repositories / NS_03_2014 / query)
sparql = SPARQLUpdateStore(http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/查询)
sparql.setQuery(
PREFIX dc:< http://purl.org/dc/elements/1.1/>
PREFIX rdfs:< http: //www.w3.org/2000/01/rdf-schema#>
PREFIX nsogi:< http://prefix.cc/nsogi>
PREFIX rdf:< http:// www.w3.org/1999/02/22-rdf -syntax-NS#>
PREFIX skos:< http://www.w3.org/2004/02/skos/core#>
PREFIX dcterms:< http://purl.org/dc/terms/>
SELECT?risultato
WHERE {
?item a skos:Concept。
?item skos:prefLabel?risultato。
过滤正则表达式(?risultato,+ type +,i)
} ORDER BY?risultato
)
#FILTER正则表达式(str(?aConcept),http://thes.bncf.firenze.sbn.it/,i)。}
sparql.setReturnFormat(JSON)
结果()结果= json.dumps(结果)
返回结果$($结果)='sparql.query()。convert()
results = results ['results'] ['bindings'] b $ b
digitale.bncf.firenze.sbn.it
digitale.bncf.firenze.sbn.it
查看相关的 documentation sparql.query()...
需要一个查询参数。
sparql = SPARQLUpdateStore(http://digitale.bncf.firenze.sbn.it/openrdf- workbench / repositories / NS_03_2014 / query)
sparql.setReturnFormat(JSON)
query =
PREFIX dc:< http://purl.org/dc/elements/1.1/>
PREFIX rdfs:< http://www.w3.org/2000/01/rdf-schema#>
PREFIX nsogi:< http://prefix.cc/nsogi>
PREFIX rdf:< http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX skos:< http://www.w3.org/2004/02/skos/core#>
PREFIX dcterms:< http://purl.org/dc/terms/>
SELECT?risultato
WHERE {
?item a skos:Concept。
?item skos:prefLabel?risultato。
filter regex(?risultato,+ type +,i)
} ORDER BY?risultato
results = sparql .query(query).convert()
我不能确定 sparql.setQuery(...)
是,但很明显这不是你想要的。
编辑:
查看源代码 setQuery(...)
确实供内部使用(例如,编写子类的人员)不是用于普通的api用户,它提取查询表单并记录查询文本 query(...)
在内部调用它
I try to obtain results bindings by this Sparql query. Through this Sparql entry point: http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query
I have the error: "TypeError: query() takes at least 2 arguments (1 given)
Thank you!!!
@app.route('/caricaArgomento/<type>', methods=['GET'])
def getArgomento(type):
#sparql = SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf- workbench/repositories/NS_03_2014/query")
sparql=SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query")
sparql.setQuery("""
PREFIX dc:<http://purl.org/dc/elements/1.1/>
PREFIX rdfs:<http://www.w3.org/2000/01/rdf-schema#>
PREFIX nsogi:<http://prefix.cc/nsogi>
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX skos:<http://www.w3.org/2004/02/skos/core#>
PREFIX dcterms:<http://purl.org/dc/terms/>
SELECT ?risultato
WHERE {
?item a skos:Concept .
?item skos:prefLabel ?risultato .
filter regex(?risultato, """+type+""", "i")
} ORDER BY ?risultato
""")
#FILTER regex(str(?aConcept), "http://thes.bncf.firenze.sbn.it/", "i").}
sparql.setReturnFormat(JSON)
results = sparql.query().convert()
results = results['results']['bindings']
results = json.dumps(results)
return results
digitale.bncf.firenze.sbn.it digitale.bncf.firenze.sbn.it
Looking at the relevant documentation sparql.query()...
requires a query argument.
sparql=SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query")
sparql.setReturnFormat(JSON)
query = """
PREFIX dc:<http://purl.org/dc/elements/1.1/>
PREFIX rdfs:<http://www.w3.org/2000/01/rdf-schema#>
PREFIX nsogi:<http://prefix.cc/nsogi>
PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX skos:<http://www.w3.org/2004/02/skos/core#>
PREFIX dcterms:<http://purl.org/dc/terms/>
SELECT ?risultato
WHERE {
?item a skos:Concept .
?item skos:prefLabel ?risultato .
filter regex(?risultato, """+type+""", "i")
} ORDER BY ?risultato
"""
results = sparql.query(query).convert()
I can't work out what the purpose of sparql.setQuery(...)
is, but clearly it's not what you want.
Edit:
Having looked at the source setQuery(...)
is really for internal use (people writing subclasses, for example), and not for regular api users. It pulls out the query form and records the query text. query(...)
calls it internally.
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