Flex新手XMLList问题 - 排序XML和XMLList [英] Flex Newbie XMLList question - Sorting XML and XMLList

问题描述

是否可以对XMLList进行排序？所有的例子，我可以找到它创建一个新的XMLListCollection是这样的：

  MyXMLListCol = new XMLListCollection（MyXMLList）; 
  

我不认为XMLListCollection在这种情况下对XMLList有任何引用，我的XMLList未排序，这是正确的吗？

我怎样才能直接排序的XMLList

所以我终于让我的搜索条件发生了变化，实际上我对此做了一个回答。
使用我从这里得到的技术：
http://freerpad.blogspot.com/2007/07/more-hierarchical-sorting-e4x-xml-for.html

<我可以想出这个：

  public function sortXMLListByAttribute（parentNode：XML，xList：XMLList，attr：String ）：void {
 // attr值必须是ints 
 var xListItems：int = xList.length（）; 
 if（xListItems！= 0）{
 var sortingArray：Array = new Array（）; 
 var sortAttr：Number = new Number（）; 
 for each（var item：xList中的XML）{
 sortAttr = Number（item.attribute（attr））; 
 if（sortingArray.indexOf（sortAttr）==  -  1）{
 sortingArray.push（sortAttr）; 
 
 //捎回删除，只需要删除所有的localName而不接触其他localNames的项目
删除parentNode.child（item.localName（））[0]; 
} 
 if（sortingArray.length> 1）{
 sortingArray.sort（Array.NUMERIC）; 
} 
 
 var sortedList：XMLList = new XMLList（）; 
（var sortedAttr：sortArray中的数字）{
 for each（var item2：xList中的XML）{
 var tempVar：Number = Number（item2.attribute（attr））; 
 if（tempVar == sortedAttr）{
 sortedList + = item2 
} 
} 
} 
 for each（var item3：sortedList中的XML）{ 
 parentNode.appendChild（item3）; 
 
 
 
 
 
 
工作得非常快，原始的XML变量更新。我知道我可能只是为了不使用XMLListCollection而重新发明轮子，但是我认为对XML和XMLLists进行排序的能力可以是非常重要的。
Is it possible to sort an XMLList? All the examples I can find on it create a new XMLListCollection like this:
MyXMLListCol = new XMLListCollection(MyXMLList);
I don't think the XMLListCollection in this case has any reference to the XMLList so sorting it would leave my XMLList unsorted, is this correct?

How can I sort the XMLList directly?

Thanks
~Mike
解决方案
So I finally got my search terms altered enough I actually churned up an answer to this.
Using the technique I got from here:
http://freerpad.blogspot.com/2007/07/more-hierarchical-sorting-e4x-xml-for.html

I was able to come up with this:
public function sortXMLListByAttribute(parentNode:XML,xList:XMLList,attr:String):void{
//attr values must be ints
var xListItems:int = xList.length();
if(xListItems !=0){
    var sortingArray:Array = new Array();
    var sortAttr:Number = new Number();
    for each (var item:XML in xList){
        sortAttr = Number(item.attribute(attr));
        if(sortingArray.indexOf(sortAttr)==-1){
            sortingArray.push(sortAttr);
        }
        //piggy back the removal, just have to remove all of one localName without touching items of other localNames
        delete parentNode.child(item.localName())[0];
    }
    if( sortingArray.length > 1 ) {
        sortingArray.sort(Array.NUMERIC);
    }

    var sortedList:XMLList = new XMLList();
    for each(var sortedAttr:Number in sortingArray){
        for each (var item2:XML in xList){
            var tempVar:Number = Number(item2.attribute(attr));
            if(tempVar == sortedAttr){
                sortedList += item2
            }
        }
    }
    for each(var item3:XML in sortedList){
        parentNode.appendChild(item3);
    }
}
}
Works pretty fast and keeps my original XML variable updated. I know I may be reinventing the wheel just to not use an XMLListCollection, but I think the ability to sort XML and XMLLists can be pretty important

                        
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