以秒为单位的时间差（作为浮点） [英] Time difference in seconds (as a floating point)

问题描述

 >>> from datetime import datetime 
>>> t1 = datetime.now（）
>>> t2 = datetime.now（）
>>> delta = t2-t1 
>>> delta.seconds 
 7 
>>> delta.microseconds 
 631000 
  

有没有办法把它作为7.631000？我可以使用时间模块，但我也需要t1和t2变量作为DateTime对象。所以如果有一个简单的方法来做到这一点，那就太好了。否则它看起来很难看：

$ p $ t1 = datetime.now（）
_t1 = time.time（）
t2 = datetime.now（）
diff = time.time（） - _t1


解决方案

combined = delta.seconds + delta.microseconds / 1E6

>>> from datetime import datetime
>>> t1 = datetime.now()
>>> t2 = datetime.now()
>>> delta = t2 - t1
>>> delta.seconds
7
>>> delta.microseconds
631000

Is there any way to get that as 7.631000 ? I can use time module, but I also need that t1 and t2 variables as DateTime objects. So if there is an easy way to do it with datettime, that would be great. Otherwise it'll look ugly:

t1 = datetime.now()
_t1 = time.time()
t2 = datetime.now()
diff = time.time() - _t1

解决方案

combined = delta.seconds + delta.microseconds/1E6

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