使用unicode粗俗分数创建紧凑/人性化的花车 [英] Create compact/human-friendly floats using unicode vulgar fractions
问题描述
例如。 4.625会变成4bb $ p
$ b 大纲是最好的,我可以拿出:
pre code进口unicodedata
$ b $ def simpl_float(数字):
vf =VULGAR FRACTION
vulgars = {0.125:unicodedata.lookup(vf +ONE EIGHTH),
0.2:unicodedata.lookup(vf +ONE FIFTH),
0.25:unicodedata.lookup(vf +ONE QUARTER),
0.375:unicodedata.lookup(vf +THREE EIGHTHS),
0.4:unicodedata.lookup(vf +TWO FIFTHS ),
0.5:unicodedata.lookup(vf +ONE HALF),
0.6:unicodedata.lookup(vf +THREE FIFTHS),
0.625:unicodedata.lookup(vf +FIVE EIGHTHS),
0.75:unicodedata.lookup(vf +THREE QUARTERS),
0.8:unicodedata.lookup(vf +FOUR FIFTHS),
0.875:unicodedata.lookup(vf +SEVEN EIGHTHS)}
decimal = int(number)
if number == decimal:
return unicode(decimal)
低俗= vulgars.get(数字 - 小数)
如果低俗:
如果小数== 0:
返回低俗
返回%d%s% (十进制,低俗)
返回%.1f%number
使用unicodedata模块非常容易,但我找不到一个好的方法来创建这些字符串。
解决方案Unicode中只有二十个这样的分数形式。这是不太可能的(因为它们只是为了向后兼容其他字符集),所以对它们进行硬编码可能足够强大。
编码分数的一般方法是使用 /
U + 2044 FRACTION SLASH。字体整形/布局引擎允许用分数斜线(例如1/2)作为倾斜的或堆叠的分数(例如1/2)来呈现数字 - 但是,我还没有遇到任何这样做(甚至简单的渲染不幸的是相当丑陋)。
进口数学
进口分数
VULGAR_FRACTIONS = {(5 ,8):'\\\⅝',...}
def compact_float(number):
parts = math.modf(number)
fraction = fractions.Fraction部分[0])
simple =(fraction.numerator,fraction.denominator)
form = VULGAR_FRACTIONS.get(simple)
return'%i%s'%(parts [1],表单)如果表单其他str(数字)
目前还不清楚处理精度的最好方法是什么例如, 1/3
),因为它取决于你的数字存在的格式和可接受的错误数量。
Are there any modules (preferably in the standard library), that can turn a float number into something the is more human friendly? Maybe it's not more human friendly, but at least more compact.
eg. 4.625 would become "4⅝"
(Bonus brownie points for recognizing pi to a reasonable precision)
This code outline was the best I could come up with:
import unicodedata
def simplify_float(number):
vf = "VULGAR FRACTION "
vulgars = {0.125 : unicodedata.lookup(vf + "ONE EIGHTH"),
0.2 : unicodedata.lookup(vf + "ONE FIFTH"),
0.25 : unicodedata.lookup(vf + "ONE QUARTER"),
0.375 : unicodedata.lookup(vf + "THREE EIGHTHS"),
0.4 : unicodedata.lookup(vf + "TWO FIFTHS"),
0.5 : unicodedata.lookup(vf + "ONE HALF"),
0.6 : unicodedata.lookup(vf + "THREE FIFTHS"),
0.625 : unicodedata.lookup(vf + "FIVE EIGHTHS"),
0.75 : unicodedata.lookup(vf + "THREE QUARTERS"),
0.8 : unicodedata.lookup(vf + "FOUR FIFTHS"),
0.875 : unicodedata.lookup(vf + "SEVEN EIGHTHS")}
decimal = int(number)
if number == decimal:
return unicode(decimal)
vulgar = vulgars.get(number - decimal)
if vulgar:
if decimal == 0:
return vulgar
return "%d%s" % (decimal, vulgar)
return "%.1f" % number
Going the other direction is pretty easy using the unicodedata module, but I couldn't find a good way to author these strings in the first place.
There are only twenty of these fraction forms in Unicode. It is unlikely that there will ever be more (as they only exist for backwards compatibility with other character sets), so hardcoding them is probably robust enough.
The general way of encoding fractions is to use ⁄
U+2044 FRACTION SLASH. Font shaping/layout engines are allowed to render numbers with a fraction slash (e.g., 1⁄2) with as a slanted or stacked fraction (e.g., ½)—however, I have not encountered any that do (and even the plain rendering is unfortunately quite ugly).
import math
import fractions
VULGAR_FRACTIONS = {(5, 8) : '\u215D', ...}
def compact_float(number):
parts = math.modf(number)
fraction = fractions.Fraction(parts[0])
simple = (fraction.numerator, fraction.denominator)
form = VULGAR_FRACTIONS.get(simple)
return '%i%s' % (parts[1], form) if form else str(number)
It's not clear what the best way is to handle precision (e.g., 1/3
) as it will depend on the format your numbers exist in and how much error is acceptable.
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