精确地从字符串分配浮点数 [英] Assign to Float from string with precision

问题描述

  String s1 = 525.880005\" ; 
 Float f = new Float（s1）; 
 System.out.println（f）; 
  

输出：
5.88

预期产出：
525.880005

解决方案

Float 只有7-8个有效数字。你的例子中的5是第9位数字。

即使它有足够的精度，我也不知道525.880005是否可以完全表示为二进制浮点数。如果精确的十进制表示对你很重要，你应该使用 BigDecimal 。

I have the following code, I want to assign a decimal value to float without losing precision.

String s1= "525.880005";
Float f = new Float(s1);
System.out.println(f);

Output: 5.88

Expected Output: 525.880005

解决方案

Float only has 7-8 significant digits of precision. The "5" in your example is the 9th digit.

Even if it had enough precision, I don't know whether 525.880005 is exactly representable as a binary floating point number. Most decimal values aren't :)

You should use BigDecimal if the exact decimal representation is important to you.

这篇关于精确地从字符串分配浮点数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！