Java中Float的最大值？ [英] Maximum value for Float in Java?

问题描述

以下问题表示Double是 -Double.MAX_VALUE 。这对于Float也是如此（即， -Float.MAX_VALUE ）？

是的， -Float.MAX_VALUE 是最大量级的负数。 float s的表示方式与 double s相同，只是存储空间的一半（以及伴随的精度损失。）由于IEEE 754中的符号由一位表示，所以翻转该位不会改变剩余位所能达到的整体幅度。

The following question indicates that the minimum value of a Double is -Double.MAX_VALUE. Is this also true for Float (i.e., -Float.MAX_VALUE)?

解决方案

Yes, -Float.MAX_VALUE is the negative number with largest magnitude. floats are represented the same way as doubles, just with half the storage space (and the accompanying loss of precision.) Since signs in IEEE 754 are represented by a single bit, flipping that bit doesn't change the overall magnitude attainable by the remaining bits.

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