从Scanner输入Java接收浮动 [英] Receiving float from Scanner input Java
问题描述
我需要一个方法来检查用户的输入是否是一个浮点数,如果是字符串或整型,它应该抛出一个异常。
我在这个方法之外声明了扫描器:
pre code> Scanner sc =新的扫描仪(System.in);
而方法定义是:
<$ p $($)$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $'
}
else {
float input = sc.nextFloat();
if(input%1 == 0){
throw new MyException(Wrong type);
}
else返回true;
$ b $ p
$ b
问题是无论如何抛出异常用户输入,所以我的问题是:我究竟做错了什么?
我知道在Java中,像1.2这样的输入被解释为double,但是如何获取从控制台的浮动呢?或者我误解了方法hasNextFloat()或整个扫描仪的工作?
到目前为止我还没有找到有用的东西
next()
public static void main(String [] args)抛出Exception {
while(true){
System.out.print(Enter a float:);
尝试{
float myFloat = input.nextFloat();
if(myFloat%1 == 0){
throw new Exception(Wrong type);
}
System.out.println(myFloat);
catch(InputMismatchException ime){
System.out.println(ime.toString());
input.next(); //从所有数据
code
$ b 结果:
UPDATE
您仍然必须处理InputMismatchException,只是在catch块中抛出自己的异常。 ($ {
> public static void main(String [] args){
Scanner input = new Scanner(System.in);
// while(true)仅用于测试
while(true){
try {
System.out.print(Enter a float:);
System.out.println(CheckFloat(input));
} catch(MyException me){
System.out.println(me.toString());
$ b private static float CheckFloat(Scanner sc)throws MyException {
try {
float input = sc.nextFloat ();
if(input%1 == 0){
throw new MyException(Wrong type);
} else {
return input;
catch(InputMismatchException ime){
sc.next(); //刷新扫描器
//重新创建自己的异常
抛出new MyException(Wrong type);
私有静态类MyException扩展异常{
//您异常详细信息
public MyException(String message){
super (信息);
$结果:
I need a method that should check whether user's input is a float, and if it is string or int it should throw an exception.
I declare the Scanner outside of the method:
Scanner sc = new Scanner(System.in);
And the method definition is:
private boolean CheckFloat(Scanner sc) throws MyException {
if(!sc.hasNextFloat()){
throw new MyException("Wrong type");
}
else {
float input = sc.nextFloat();
if(input%1==0) {
throw new MyException("Wrong type");
}
else return true;
}
}
The problem is that the exception is thrown no matter what the user types in, so my question is: what exactly do I do wrong?
I know that in Java an input like 1.2 is interpreted as double, but how to take a float from the console then? Or do I misunderstand working of the method hasNextFloat() or the whole Scanner?
I haven't found anything helpful so far
解决方案 Since you're using nextFloat()
you must be sure that you enter a floating number, otherwise clear the scanner with next()
public static void main(String[] args) throws Exception {
while (true) {
System.out.print("Enter a float: ");
try {
float myFloat = input.nextFloat();
if (myFloat % 1 == 0) {
throw new Exception("Wrong type");
}
System.out.println(myFloat);
} catch (InputMismatchException ime) {
System.out.println(ime.toString());
input.next(); // Flush the buffer from all data
}
}
}
Results:
UPDATE
You still have to handle the InputMismatchException, just throw your own exception in the catch block.
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
// while (true) just for testing
while (true) {
try {
System.out.print("Enter a float: ");
System.out.println(CheckFloat(input));
} catch (MyException me) {
System.out.println(me.toString());
}
}
}
private static float CheckFloat(Scanner sc) throws MyException {
try {
float input = sc.nextFloat();
if (input % 1 == 0) {
throw new MyException("Wrong type");
} else {
return input;
}
} catch (InputMismatchException ime) {
sc.next(); // Flush the scanner
// Rethrow your own exception
throw new MyException("Wrong type");
}
}
private static class MyException extends Exception {
// You exception details
public MyException(String message) {
super(message);
}
}
Results:
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