为什么Java编译器抱怨对原始类型使用foreach？ [英] Why does the Java Compiler complain on using foreach with a raw type?

问题描述

在Java中的for-each循环中使用泛型时，出现了一个奇怪的编译器错误。这是一个Java编译器错误，还是我真的在这里丢失的东西？

这是我的整个类：

  public class Generics< T extends Object> {
 public Generics（T myObject）{
 //我真的不需要myObject 
} 
 
 public List< String> getList（）{
 List< String> list = new ArrayList< String>（）; 
 list.add（w00t StackOverflow）; 
返回列表; 
 
 
 public static void main（String ... a）{
泛型泛型= new泛型（new Object（））; 
 for（String s：generics.getList（））{
 System.out.println（s）; 
 
 
 
 
 
 $ b 
编译器抱怨
如果我做了这个微妙的变化，它编译：
 
  pre>  public static void main（String ... a）{
 Generics<？>泛型= new泛型（new Object（））; 
 for（String s：generics.getList（））{
 System.out.println（s）; 
 
 
 
 
我知道 getList（） 确实使用了泛型，但它在我认为是完全不相关的方式中使用它们。我可以理解这一点，如果我试图迭代类型T的东西， getList（）返回一个 List< T> 或什么的，但这不是这种情况。返回类型的 getList（）应该与T完全没有关系，不应该在意我是否使用我的泛型对象的原始类型或不正确？这些应该不是完全不相关的，或者我真的在这里丢失了什么？
 
 
 
请注意，代码也编译，如果我这样做，我认为应该是相当于第一个也是：
 
 pre $  public static void main（String ... a）{
泛型泛型= new泛型（new Object（））; 
列表< String> list = generics.getList（）; 
 for（String s：list）{
 System.out.println（s）; 
 
 
 $ / code $ / pre 
 
解决方案
不同之处在于，当你使用原始类型时，所有成员签名中的泛型引用都被转换为原始格式。所以有效地你调用一个方法，现在有这样的签名：
 
 $ p $  List getList（）
 
 code> 

现在至于为什么你的最终版本编译 - 尽管它，如果你使用 -Xlint ：

  Generics.java:16：warning：[unchecked] unchecked conversion 
 List< ;字符串> list = generics.getList（）; 
 
  

类似于：



  List list = new ArrayList（）; 
列表< String> strings = list; 
  

...也可以编译，但在 -Xlint 。

故事的寓意：不要使用原始类型！

I got a strange compiler error when using generics within a for-each loop in Java. Is this a Java compiler bug, or am I really missing something here?

Here is my whole class:

public class Generics<T extends Object> {
  public Generics(T myObject){
    // I didn't really need myObject
  }

  public List<String> getList(){
    List<String> list = new ArrayList<String>();
    list.add("w00t StackOverflow");
    return list;
  }

  public static void main(String...a){
    Generics generics = new Generics(new Object());
    for(String s : generics.getList()){
      System.out.println(s);
    }
  }
}

The compiler is complaining about the line with the for-each: "Type mismatch cannot convert from element type Object to String."
If I make this subtle change, it compiles:

public static void main(String...a){
  Generics<?> generics = new Generics(new Object());
  for(String s : generics.getList()){
    System.out.println(s);
  }
}

I know getList() does use generics, but it uses them in what I thought was a completely unrelated way. I could understand this if I were trying to iterate over something of type T and getList() returned a List<T> or something, but that's not the case here. The return type of getList() should have absolutely nothing to do with T and shouldn't care whether I use the raw type for my Generics object or not...right? Shouldn't these be completely unrelated, or am I really missing something here?

Note that the code also compiles if I do this, which I thought should have been equivalent to the first as well:

public static void main(String...a){
  Generics generics = new Generics(new Object());
  List<String> list = generics.getList();
  for(String s : list){
    System.out.println(s);
  }
}

解决方案

The difference is that when you use the raw type, all the generic references within the member signatures are converted to their raw forms too. So effectively you're calling a method which now has a signature like this:

List getList()

Now as for why your final version compiles - although it does, there's a warning if you use -Xlint:

Generics.java:16: warning: [unchecked] unchecked conversion
    List<String> list = generics.getList();
                                        ^

This is similar to:

 List list = new ArrayList();
 List<String> strings = list;

... which also compiles, but with a warning under -Xlint.

The moral of the story: don't use raw types!

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