XSLT For-Each循环从枚举标记中获取数据？ [英] XSLT For-Each loop to get data from enumerated tags?
问题描述
它们的代码看起来像
< Root>
<科目>
< ...更多XML数据>
< Data>
< ...其他XML数据>
< Demographic_Information>
< Age1> 33< / Age1>
< Age2> 66< / Age2>
< Age3 />
< Age4 />
< Age5 />
< Age6 />
< Age7 />
< Age8 />
< Age9 />
< Age10 />
< Gender1> M< / Gender1>
< Gender2> F< / Gender2>
< Gender3 />
< Gender4 />
< Gender5 />
< Gender6 />
< Gender7 />
< Gender8 />
< Gender9 />
< Gender10 />
< Race1> W< / Race1>
< Race2> H< / Race2>
< Race3 />
< Race4 />
< Race5 />
< Race6 />
< Race7 />
< Race8 />
< Race9 />
< Race10 />
< / Demographic_Information>
< / ...其他XML数据>
< / Data>
< / ...更多XML数据>
< /科目>
< / Root>
我只需循环执行此操作，并确保Age1，Gender1和Race1进入我的数据像
< Person subject =1>
<年龄> 33< /年龄>
<性别> M< /性别>
< Race> W< / Race>
< / Person>
< Person subject =2>
<年龄> 66< /年龄>
<性别> F< /性别>
< Race> A< / Race>
< / Person>
这是更大集合中数据的一个子集，但是我需要把它变成这种格式if可能。我相信它可以做，我只是不知道如何去做。
我的XSLT是Microsoft Visual Studio 2008中的1.0版。我以
< xsl：template match =/ Root / Subjects>
***修改后可以提供我的问题的更好的示例。
下面是一个快速的刺法 - 我将继续看这个来找到效率，但我想给你一个答案。 >
编辑：感谢@MartinHonnen提供了一个很好的简化。
XSLT：
<？xml version =1.0encoding =UTF-8？>
< xsl：stylesheet xmlns：xsl =http://www.w3.org/1999/XSL/Transformversion =1.0>
< xsl：output omit-xml-declaration =yesindent =yes/>
< xsl：strip-space elements =*/>
< xsl：variable
name =vNums
select ='0123456789'/>
match =Demographic_Information / *
use =translate（name（），translate（name ），$ vNums，''），''）/>
< xsl：template match =/ *>
< Demographic_Information>
< xsl：apply-templates
select =* [generate-id（）=
generate-id（key（
'kElemByNumber'，
translate name（），translate（name（），$ vNums，''），
''
））[1]）] [normalize-space（）]>
data-type =number />
< / xsl：apply-templates>
< / Demographic_Information>
< / xsl：template>
< xsl：template match =*>
< Person subject ={position（）}>
mode =children>
< xsl：sort select =name（）/>
< / xsl：apply-templates>
< / Person>
< / xsl：template>
< xsl：template match =*mode =children>
< / xsl：element>
< / xsl：template>
< / xsl：stylesheet>
...应用于提供的源XML：
< Demographic_Information>
< Age1> 33< / Age1>
< Age2> 66< / Age2>
< Age3 />
< Age4 />
< Age5 />
< Age6 />
< Age7 />
< Age8 />
< Age9 />
< Age10 />
< Gender1> M< / Gender1>
< Gender2> F< / Gender2>
< Gender3 />
< Gender4 />
< Gender5 />
< Gender6 />
< Gender7 />
< Gender8 />
< Gender9 />
< Gender10 />
< Race1> W< / Race1>
< Race2> H< / Race2>
< Race3 />
< Race4 />
< Race5 />
< Race6 />
< Race7 />
< Race8 />
< Race9 />
< Race10 />
< / Demographic_Information>
...想要的结果是产生的：
< Demographic_Information>
< Person subject =1>
<年龄> 33< /年龄>
<性别> M< /性别>
< Race> W< / Race>
< / Person>
< Person subject =2>
<年龄> 66< /年龄>
<性别> F< /性别>
< Race> A< / Race>
< / Person>
< / Demographic_Information>
I've been provided an SML file where the designer (not in my company, so I have no control over this) has created some data that I need to consume; but they setup enumerated tags, so I'm having a difficult time creating a loop to read the data.
Their code looks like
<Root>
<Subjects>
<...more XML Data>
<Data>
<...other XML Data>
<Demographic_Information>
<Age1>33</Age1>
<Age2>66</Age2>
<Age3 />
<Age4 />
<Age5 />
<Age6 />
<Age7 />
<Age8 />
<Age9 />
<Age10 />
<Gender1>M</Gender1>
<Gender2>F</Gender2>
<Gender3 />
<Gender4 />
<Gender5 />
<Gender6 />
<Gender7 />
<Gender8 />
<Gender9 />
<Gender10 />
<Race1>W</Race1>
<Race2>H</Race2>
<Race3 />
<Race4 />
<Race5 />
<Race6 />
<Race7 />
<Race8 />
<Race9 />
<Race10 />
</Demographic_Information>
</...other XML Data>
</Data>
</...more XML Data>
</Subjects>
</Root>
I just need to loop through this, and ensure that Age1, Gender1, and Race1 go into my data like
<Person subject="1">
<Age>33</Age>
<Gender>M</Gender>
<Race>W</Race>
</Person>
<Person subject="2">
<Age>66</Age>
<Gender>F</Gender>
<Race>A</Race>
</Person>
This is a subset of data inside a larger set, but I need to get it into this format if possible. I'm sure it can be done, I just don't know how to go about it.
My XSLT is version 1.0 in Microsoft Visual Studio 2008. I start with
<xsl:template match="/Root/Subjects">
***Modified to provide a better sample of my issue.
Here's a quick stab that works - I'm going to continue to look at this to find efficiencies, but I wanted to get you an answer.
EDIT: thanks to @MartinHonnen for a nice simplification.
When this XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable
name="vNums"
select="'0123456789'"/>
<xsl:key
name="kElemByNumber"
match="Demographic_Information/*"
use="translate(name(), translate(name(), $vNums, ''), '')"/>
<xsl:template match="/*">
<Demographic_Information>
<xsl:apply-templates
select="*[generate-id() =
generate-id(key(
'kElemByNumber',
translate(name(), translate(name(), $vNums, ''),
''
))[1])][normalize-space()]">
<xsl:sort
select="translate(name(), translate(name(), $vNums, ''), '')"
data-type="number"/>
</xsl:apply-templates>
</Demographic_Information>
</xsl:template>
<xsl:template match="*">
<Person subject="{position()}">
<xsl:apply-templates
select="key('kElemByNumber', position())"
mode="children">
<xsl:sort select="name()"/>
</xsl:apply-templates>
</Person>
</xsl:template>
<xsl:template match="*" mode="children">
<xsl:element name="{translate(name(), $vNums, '')}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
...is applied to the provided source XML:
<Demographic_Information>
<Age1>33</Age1>
<Age2>66</Age2>
<Age3/>
<Age4/>
<Age5/>
<Age6/>
<Age7/>
<Age8/>
<Age9/>
<Age10/>
<Gender1>M</Gender1>
<Gender2>F</Gender2>
<Gender3/>
<Gender4/>
<Gender5/>
<Gender6/>
<Gender7/>
<Gender8/>
<Gender9/>
<Gender10/>
<Race1>W</Race1>
<Race2>H</Race2>
<Race3/>
<Race4/>
<Race5/>
<Race6/>
<Race7/>
<Race8/>
<Race9/>
<Race10/>
</Demographic_Information>
...the wanted result is produced:
<Demographic_Information>
<Person subject="1">
<Age>33</Age>
<Gender>M</Gender>
<Race>W</Race>
</Person>
<Person subject="2">
<Age>66</Age>
<Gender>F</Gender>
<Race>A</Race>
</Person>
</Demographic_Information>
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