引用多个外键php mysql [英] referencing multiple foreign keys php mysql
问题描述
我对PHP / MySQL非常陌生,遇到了一些麻烦。帮助将不胜感激。
我有两个表格布局如下:
$ b
表队
team_id,team_name
表格
game_id,game_time,team1_id,team2_id,location
$ b
schedule.team1_id和schedule.team2_id都是team.team_id的外键。
我试图用team1_id和team2_id来引用team_name,但是我似乎只能得到team1的名字。这是我用过的查询不成功的。
SELECT * FROM team
AS t JOIN schedule AS s
ON t.team_id = s.team1_id
WHERE位置='1';
我试图输出数据:
while(mysql_fetch_assoc($ result)){
echo $ row ['team_name'];
$ b $ p
$ b 这很明显,为什么这样做不起作用,只加入我需要的一列。帮帮我!我完全失去了如何解决这个问题。我相信有一个简单的解决方案,但我似乎无法找到它!
解决方案想要查询的结果看起来像,但我假设你想获得有关两个参与每个游戏的团队的信息。为此,您必须加入团队
表格两次:
SELECT t1.name,t2.name,s。*
FROM schedule AS
INNER JOIN team AS t1 ON t1.team_id = s.team1_id
INNER JOIN team AS t2 ON t2 .team_id = s.team2_id
WHERE s.location ='1';
I'm very new to php/MySQL and I'm having a bit of trouble. Help would be much appreciated.
I have 2 tables laid out as such:
table team
team_id,team_name
table schedule
game_id,game_time,team1_id,team2_id,location
schedule.team1_id and schedule.team2_id are both foreign keys to team.team_id.
I'm trying to reference team_name using team1_id and team2_id but I can only ever seem to get the name for team1. This is the query I've used unsuccessfully.
SELECT * FROM team
AS t JOIN schedule AS s
ON t.team_id = s.team1_id
WHERE location='1';
My attempt to output the data:
while (mysql_fetch_assoc($result)) {
echo $row['team_name'];
}
It's quite obvious to me why this isn't working, as the tables are joined on only one of the columns I need. Help! I'm completely lost as to how to solve this problem. I believe there is a simple solution, but I can't seem to find it!
解决方案 It's not quite clear on what you would like the results of your query to look like, but I am assuming you would like to get information about both teams involved in each game. To do so, you'll have to join the team
table twice:
SELECT t1.name, t2.name, s.*
FROM schedule AS s
INNER JOIN team AS t1 ON t1.team_id = s.team1_id
INNER JOIN team AS t2 ON t2.team_id = s.team2_id
WHERE s.location='1';
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