PHP时间间隔 [英] PHP time intervals

问题描述

我正在寻找一个解决方案，似乎它应该是非常简单的，但似乎并没有在这里找到任何好的答案，我似乎无法得到它自己的工作。

我正在寻找的是设置一个开始时间，一个结束时间，然后在给定的时间间隔之间迭代一组次。例如，上午9:00 - 下午5:00是开始时间，在这些时间之间以半小时为间隔返回的值是9:30，10:00，10:30，11:00等。 / p>

下面是一些伪代码，因为我不确定我需要在这里插入什么（至少我没有尝试过） （$ i = *开始时间*; $ i = *结束时间*; $ i + = *时间间隔*）{

  
 echo $ i; 
 
 
 
 $ b $ p 
 $ b $ p 
 $ =h2_lin>解决方案

关闭我的头顶。



  $ start = new DateTime（'2013-08-14 09:00:00'）; 
 $ end = new DateTime（'2013-08-14 17:00:00'）; 
 $ interval = new DateInterval（'PT30M'）; 
 $ period = new DatePeriod（$ start，$ interval，$ end）; 
 $ b foreach（$ period as $ dt）
 {
 //做某事
 echo $ dt->格式（'H：iA'）; 
} 
  

链接


• 日期时间


• DateInterval


• DatePeriod

I'm looking for a solution to something which seems like it should be pretty simple, but it doesn't seem that I can find any good answers on here, and I can't seem to get it to work myself.

What I'm looking for is to set a start time, an end time, and then iterate through a set of times between given a time interval. Say, for example, 9:00 AM - 5:00 PM are the start times, and the values returned between these times at half hour intervals are 9:30, 10:00, 10:30, 11:00, etc.

Here's some pseudo-code, because I'm not exactly sure what I need to plug in here (at least nothing I've tried has worked)...

for ($i = *start time*; $i = *end time*; $i += *time interval*) {
    echo $i;
}

Any ideas on this?

解决方案

Off of the top of my head. You can tweak as necessary.

$start    = new DateTime('2013-08-14 09:00:00');
$end      = new DateTime('2013-08-14 17:00:00');
$interval = new DateInterval('PT30M');
$period   = new DatePeriod($start, $interval, $end);

foreach ($period as $dt)
{
    // do something
    echo $dt->format('H:iA');
}

Links

• DateTime
• DateInterval
• DatePeriod

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