为循环内部分配变量 [英] Assign variables inside for loops

问题描述

我试着为（（i = 0; i <2; i ++））的小代码是

 做p $ i = \\pra $ i \;完成
  

期望的输出是：
变量必须被赋值

  p0 =pra0
 p1 =pra1
  

但是bash将这个命令作为命令获得输出结果是

pre $ = code> p0 =pra0 ：command not found
p1 =pra1：找不到命令

谢谢

解决方案使用 eval 可以根据需要评估和存储值： $ b

 做eval p $ i = \\pra $ i \;完成
 $ echo $ p1 
 pra1 
  

---

或者更好地用 declare （ $ echo $ p1
pra1

I am trying a small code which is

for(( i =0;i<2;i++ )); do p$i=\"pra$i\"; done

expected output is: Variable must be assigned

p0="pra0"
p1="pra1"

But bash is taking that as command and am getting output as

p0="pra0": command not found
p1="pra1": command not found

Thanks

解决方案

Use eval to have the value evaluated and stored as you want:

$ for(( i =0;i<2;i++ )); do eval p$i=\"pra$i\"; done
$ echo $p1
pra1

---

Or better with declare (thanks chepner as always!):

$ for(( i =0;i<2;i++ )); do declare "p$i=pra$i"; done
$ echo $p1
pra1

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