从for循环找到最大值 [英] Finding the maximum value from a for loop

问题描述

我创建的代码在寻找回文数字时给了我成千上万的解决方案。任务是找到可能的最高数字：

pre $ public static void main（String [] args）{
long产品; （int j = 999; j> = 100; j--）{
;
outer：for（int i = 999; i> = 100; i--） product = j * i;
if（reverse（product））{
System.out.printf（％d *％d =％d％n，i，j，product）;
继续;



$ b private static final boolean reverse（long value）{
String str = String.valueOf（value）;
return str.equals（new StringBuilder（str）.reverse（）。toString（））;
}}


我怎样才能让代码只显示最高的值for循环创建？

解决方案

解决方案描述在这个答案在代码：

  long highest_palindrome = 0L; 
 int storeI = 0; 
 int storeJ = 0; 
长的产品; （int j = 999; j> = 100; j--）{
; 
 outer：for（int i = 999; i> = 100; i--） product = j * i; 
 if（product< highest_palindrome）break; 
 if（reverse（product））{
 if（product> highest_palindrome）{
 highest_palindrome = product; 
 storeI = i; 
 storeJ = j; 
} 
继续; 
 
 
 
 $ b System.out.printf（％d *％d =％d％n，storeI，storeJ，highest_palindrome）; 
  

I have created code that gives me thousands of solutions when looking for palindromic numbers. The task is to find the highest number possible:

 public static void main(String[] args) {
        long product;
        outer: for (int i = 999; i >= 100; i--) {
            for (int j = 999; j >= 100; j--) {
                product = j * i;
                if (reverse(product)) {
                    System.out.printf("%d * %d = %d%n", i, j, product);
                    continue;
                }
            }
        }
    }
    private static final boolean reverse(long value) {
        String str = String.valueOf(value);
        return str.equals(new StringBuilder(str).reverse().toString());
    }}

How can I make it so that the code only displays the highest value that the for loop creates?

解决方案

The solution decribed in this answer in code:

long highest_palindrome = 0L;
int storeI = 0;
int storeJ = 0;
long product;
outer: for (int i = 999; i >= 100; i--) {
    for (int j = 999; j >= 100; j--) {
        product = j * i;
        if (product < highest_palindrome) break;
        if (reverse(product)) {
            if (product > highest_palindrome) {
                highest_palindrome = product;
                storeI = i;
                storeJ = j;
            }
            continue;
        }
    }
}

System.out.printf("%d * %d = %d%n", storeI, storeJ, highest_palindrome);

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