JavaScript - 比较两个多维数组 [英] JavaScript - Compare two multidimensional arrays
问题描述
第一个是类似于code>(['one','one','three'],[ '四','五',五'',['一','一','一'])
第二个就是这个(['one','one','nine'],['one','one','one'],['two','two'], ['two','two','two'] ...)
现在,我想要找到匹配的第一个索引第一个数组的第一个数组,但第二个数组中的至少两个索引的位置必须匹配,例如:
first_array( ['one', 'one','three'],['four','five',five'],['one','one','one']) 和输出将是例如。 'b 我已经尝试了 但是我经常得到'不匹配',虽然有匹配。 预先感谢 工作示例 I have two multidimensional arrays: first is something like and the second one is like this Now, what I want is to find match first index of first array with second array, but position of at least first two indexes from boths array must match also, eg.: first_array (['one','one','three'],['four','five',five'],['one','one','one']) will match second_array (['one','one','nine'],['one','one','one'],['two','two']['two','two','two']...) and output would be eg. 'alert('Match.'). I have tried but I constantly get 'No match' although there is a match.
P.S. in 'for' loop, my i is i<1 because I want to compare only first index of first_array with complete second_array. Thanks in advance Working Example http://jsfiddle.net/2nxBb/1/ 这篇关于JavaScript - 比较两个多维数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
$ p
$ b $ second_array( ['one','one','nine'] ,['one', 'two','two','two','two','two'] ...)
$ b
for(i = 0; i <1; i ++){
if(first_array [0] == second_array)console.log('Match');
else console.log('No match');
}
P.S.在'for'循环中,我的i是< 1,因为我只想比较first_array的第一个索引和完整的second_array。
var md1 = [['one','one','three'],[' , '五', '5'],[ '一', '一', '一']];
var md2 = [['one','one','nine'],['one','one','one'],['two','two'], [ '2', '2', '2']];
//遍历第一个数组中的所有元素
for(var x = 0; x< md1.length; x ++){
//迭代第二个数组中的所有元素
for(var y = 0; y< md2.length; y ++){
/ *这使得我们比较第一个数组中的所有元素
到第二个数组中的每个元素
由于md1 [x]保持固定,而md2 [y]遍历第二个数组。
我们比较条件
* /
中每个数组的前两个索引if(md1 [x] [0] == md2 [y] [0]& md1 [x ] [1] == md2 [y] [1]){
alert(match found);
alert(索引为+ x +的数组1元素与索引为+ y的数组2元素匹配;
$ / / strong> http://jsfiddle.net/2nxBb/1/ (['one','one','three'],['four','five',five'],['one','one','one'])
(['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']...)
for(i=0; i<1; i++){
if(first_array[0] == second_array) console.log('Match');
else console.log('No match');
}
var md1 = [['one','one','three'],['four','five','five'],['one','one','one']];
var md2 = [['one','one','nine'],['one','one','one'],['two','two'],['two','two','two']];
//Iterate through all elements in first array
for(var x = 0; x < md1.length; x++){
//Iterate through all elements in second array
for(var y = 0; y < md2.length; y++){
/*This causes us to compare all elements
in first array to each element in second array
Since md1[x] stays fixed while md2[y] iterates through second array.
We compare the first two indexes of each array in conditional
*/
if(md1[x][0] == md2[y][0] && md1[x][1] == md2[y][1]){
alert("match found");
alert("Array 1 element with index " + x + " matches Array 2 element with index " + y);
}
}
}