Django模板中的嵌套循环 [英] Nested loop in Django template

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问题描述

我无法理解这一点。我需要以某种方式访问​​父循环中的对象,但我不知道如何。这是我到目前为止所做的。我使用 XXX 标记了代码中存在问题的部分:
$ b

模板

  {%for item in ingrcat%} 
< h2> {{item.name}}< / h2>
< ul>
{%for ingr in XXX%}
< li>< a href =#id =i {{ingr.id}}> {{ingr.name}}< ; / A>< /锂>
{%endfor%}
< / ul>
{%endfor%}

XXX - 应该是

查看:

  def home(request):$ b $如果request.user.is_authenticated():
username = request.user.username
email = request.user.email
foods = Food.objects.filter(user = request.user).order_by('name')
ingredients = Ingredience.objects.filter(user = request.user ).order_by('name')
ingrcat = IngredienceCategory.objects.filter(user = request.user)

context = {}
for i in ingredients:
context [i.category.name.lower()] = context.get(i.category.name.lower(),[])+ [i]

newcontext = {'foods':食物,配料:配料,'ingrcat':ingrcat,'用户名':用户名,'email':电子邮件,}
else:
context = {}
newcontext = {}
$ b $ context = dict(context.items()+ newcontext.items())

return render_to_response('home.html',context,context_instance = RequestContext(request))

Models:

  from django.db import models $ b $ from django.contrib.auth.models import User 

类IngredienceCategory(models.Model):
name = models.CharField(max_length = 30)
user = models.ForeignKey(User,null = True,blank = True )
$ b $ class Meta:
verbose_name_plural =元素类别

def __unicode __(self):
返回self.name


类成分(models.Model):
name = models.CharField(max_length = 30)
category = models.ForeignKey(IngredienceCategory,null = True,blank = True)
user = models.ForeignKey(User,null = True,blank = True)

class Meta:
verbose_name_plural =Ingredients
$ b $ def __unicode __(self):
return self.name


class Food(models.Model):
name = models.CharField(max_length = 30)
ingredients = models.ManyToManyField(Ingredience)
html_id = models.CharField(max_length = 30,null = True,blank = True)
user = models.ForeignKey(User,null = True,blank = True)
$ b $ class Meta:
verbose_name_plural =Foods
$ b $ def __unicode __(self):
return self.name


解决方案

关系。

pre $ lt; code> {%for item in ingrcat%}
< h2> {{item.name}}< ; / H2>
< ul>
{item for item.ingredience_set.all%中的%%}
< li>< a href =#id =i {{ingr.id}}> {{ingr。 name}}< / a>< / li>
{%endfor%}
< / ul>
{%endfor%}

查看文档:

https:// docs。 djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward


I can't get my head around this. I need to somehow access the object in the parent loop but I'm not sure how. Here is what I've come up with so far. I marked the problematic area in the code with XXX:

Template:

{% for item in ingrcat %}
    <h2>{{ item.name }}</h2>
    <ul>
        {% for ingr in XXX %}
        <li><a href="#" id="i{{ ingr.id }}">{{ ingr.name }}</a></li>
        {% endfor %}
    </ul>
{% endfor %}

XXX - should be a list of ingredients belonging to the ingredience category which is currently being looped through in the parent loop.

View:

def home(request):
    if request.user.is_authenticated():
        username = request.user.username
        email = request.user.email
        foods = Food.objects.filter(user=request.user).order_by('name')
        ingredients = Ingredience.objects.filter(user=request.user).order_by('name')
        ingrcat = IngredienceCategory.objects.filter(user=request.user)

        context = {}
        for i in ingredients:
            context[i.category.name.lower()] = context.get(i.category.name.lower(), []) + [i]

        newcontext = {'foods': foods, 'ingredients': ingredients, 'ingrcat': ingrcat, 'username': username, 'email': email,}
    else:
        context = {}
        newcontext = {}

    context = dict(context.items() + newcontext.items())

    return render_to_response('home.html', context, context_instance=RequestContext(request))

Models:

from django.db import models
from django.contrib.auth.models import User

class IngredienceCategory(models.Model):
    name = models.CharField(max_length=30)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
        verbose_name_plural = "Ingredience Categories"

    def __unicode__(self):
        return self.name


class Ingredience(models.Model):
    name = models.CharField(max_length=30)
    category = models.ForeignKey(IngredienceCategory, null=True, blank=True)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
         verbose_name_plural = "Ingredients"

    def __unicode__(self):
        return self.name


class Food(models.Model):
    name = models.CharField(max_length=30)
    ingredients = models.ManyToManyField(Ingredience)
    html_id = models.CharField(max_length=30, null=True, blank=True)
    user = models.ForeignKey(User, null=True, blank=True)

    class Meta:
        verbose_name_plural = "Foods"

    def __unicode__(self):
        return self.name

解决方案

You can use backwards relationships.

{% for item in ingrcat %}
<h2>{{ item.name }}</h2>
<ul>
    {% for ingr in item.ingredience_set.all %}
    <li><a href="#" id="i{{ ingr.id }}">{{ ingr.name }}</a></li>
    {% endfor %}
</ul>
{% endfor %}

See documentation:

https://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward

这篇关于Django模板中的嵌套循环的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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