计算系列的总和 [英] Compute sum of series

问题描述

我需要这样的输出：

 如果n = 3; 
 
x = function_name（n）
  

我需要 x = 11。
$ b

 如果n = 5; 
 
x = function_name（n）
  

我需要 x = 45 。

我相信我需要一个for循环来迭代;但是我发现很难迭代递增值本身。

解决方案

inc = 2;
sum = 1;
next = 1;

n = input（'what is n？\\\
'）;

for i = 2：n
next = next + inc;
sum = sum + next;
inc = inc + 2;
end

disp（'sum is'）;
disp（sum）;


I need to compute the sum of this series

I need the output this way:

If n = 3;

x = function_name(n)

I need to get x = 11.

If n = 5;

x = function_name(n)

I need to get x = 45.

I believe I need a for-loop to iterate; but am finding it difficult to iterate the increment value itself.

解决方案

inc=2;
sum=1;
next=1;

n=input('what is n?\n');

for i=2:n
    next=next+inc;
    sum=sum+next;
    inc=inc+2;
end

disp('sum is ');
disp(sum);

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